anonymous
  • anonymous
midpoint H(13,8),X(-6,-6) i got two different answers the fist time i did i got 3.5, 1 then got this answer 2 , 1 which one is right 7
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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austinL
  • austinL
\(\normalsize{Midpoint}=\Large{(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})}\)
anonymous
  • anonymous
|dw:1378240792790:dw| so is that right
anonymous
  • anonymous
3.5, 1 is right

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austinL
  • austinL
Yes, but again exact forms are typically best.
anonymous
  • anonymous
so what one is it
austinL
  • austinL
You have the correct answer, but you have it in "approximate" form.
anonymous
  • anonymous
10.5 and -6 is it right
austinL
  • austinL
\(\normalsize{Midpoint}=\Large{(\frac{13+(-6)}{2},\frac{8+(-6)}{2})}\)
anonymous
  • anonymous
(3.5, 1) i was right the first time wow lol
austinL
  • austinL
That is what I said -_-
anonymous
  • anonymous
sorry

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