anonymous
  • anonymous
What type is the curve and sketch the graph. Do not plot points. 4x^2 + y^2 = 1 I know it's an ellipse, but how do I tell how tall and how wide it should be??
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Compare to the general formula for an ellipse: \[\left(\frac{x}{a}\right)^2+\left(\frac{y}{b}\right)^2=1\] \(a\) is the length of the horizontal "radius" and \(b\) is the length of the vertical "radius".
anonymous
  • anonymous
Should I do anything with the 4?
anonymous
  • anonymous
so it would be x= 1/4 and -1/4 and y = 1, -1. for the edges of the ellipse?

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anonymous
  • anonymous
My book is saying that it should be 1/2 instead of 1/4th?
anonymous
  • anonymous
Sorry, I mean \(a^2=\dfrac{1}{4}\), which means \(a=\dfrac{1}{2}\).
anonymous
  • anonymous
OH, perfect sense now
jdoe0001
  • jdoe0001
\(\bf \cfrac{(x-h)^2}{a^2}+\cfrac{(y-k)^2}{b^2}=1\\ -------------\\ 4x^2 + y^2 = 1 \implies \cfrac{(x-0)^2}{\frac{1}{4}}+\cfrac{(y-0)^2}{1} = 1\)

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