anonymous
  • anonymous
Solve using the square root method. Round to the nearest tenth, if necessary. x2 + 17 = 0 {10.7} {-4.1, 4.1} {-17, 17} No real solution
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
sorry my being slow im in 9th trying my best to get to 10th
phi
  • phi
you have \[ x^2 + 17 = 0 \] the first step is add -17 to both sides \[ x^2 + 17-17 = 0-17 \] and simplify
phi
  • phi
Can you simplify \[ x^2 + 17-17 = 0-17 \] ? you should get \[ x^2 = -17\] now this is important: there is no (real) number times itself that will be negative

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phi
  • phi
normally you would take the square root of both sides \[ \sqrt{x^2} = \sqrt{-17} \\ x = \sqrt{-17} \] but x will not be a real number.
phi
  • phi
if you type sq rt of -17 into your calculator, it will complain
phi
  • phi
I assume you figured out the answer is "no real solution"

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