anonymous
  • anonymous
I know the answers but I don't know how to solve it Suppose a bin at a used clothing store contains 30 pair of shoes, but the 60 shoes are all mixed up in the bin a. how many sets of two shoes (paired or unpaired) can be drawn from the bin? b. How man of those two shoe sets in (a) are pairs? c. how many four shoe sets can be drawn? How many of these consist of matched pairs?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
What are you answers?
anonymous
  • anonymous
a I already figuired it out its 1770 and all I did was\[_{60} C _{2}\] ... Im not sure how to figure out b and c ... b is 30 and c is 487635 and 435
anonymous
  • anonymous
What math class are you taking? I think I might be missing something here....

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anonymous
  • anonymous
Probability and Statistics
anonymous
  • anonymous
It's been a while and I can't promise good advice, but I can offer a few thoughts if you like...
anonymous
  • anonymous
Yes! That would be great! Thanks I am actually just having trouble understading what they are asking and picturing it, so any advice or tips will help
anonymous
  • anonymous
a. There are a total of 60 shoes, so without replacement it is only possible to draw out 30 sets of two shoes. With replacement would be a huge number.... b. I am clueless on this one. c. I would think that since there are 60 shoes, only 15 four shoe sets can be drawn without replacement. With replacement, clueless...
anonymous
  • anonymous
Thanks!
anonymous
  • anonymous
Did I help any? I feel like I'm totally off base as I think more about it.
anonymous
  • anonymous
a little, lol, It makes sense and I get your point of view but its more complicated than that lol , That is why I am having alot of trouble with it.. I believe wha you answered for a, is actually true for b. As to C I have no Idea.... haha.. Thank you so much anyway!
anonymous
  • anonymous
Try this on for size..... If there are 9 people in the room and we each shake hands with everyone else, how many handshakes is that? \(\dfrac{8!}{2!}\) because, my first round of handshakes, I shake hands with 8 other people - shaking hands with myself doesn't count. Divided by 2 because me shaking hands with you is the same as you shaking hands with me.
goformit100
  • goformit100
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anonymous
  • anonymous
That makes alot more sense!! Thank yo soo much!

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