anonymous
  • anonymous
suppose the cost of electrical energy for your house is $0.14/kw-hr and your electric bill for the past month (30 days) was $110.assuming the power delivered is constant over the entire 30 days, what is the power being used? If the voltage is 120V, what is the current being drawn? If part of teh electrical use is a 100W lightbulb that is on continuously, what percentage of your electrical usage can be saved by turning it off?
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
So three parts: the power used, the Voltage, and the percent saved
anonymous
  • anonymous
have you read your book for this class?
anonymous
  • anonymous
yes. But I am still somewhat confused with power, current, etc; and the conversions between them.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
I have P=de/dt E=QV P=IV
anonymous
  • anonymous
but now that I think about it, I think the units confuse me the most. It takes me a while to figure them out
anonymous
  • anonymous
what class is this for again?
anonymous
  • anonymous
This is in my physics class. We are working on electricity
anonymous
  • anonymous
k. I'll try to find an answer and see if that's what I get
anonymous
  • anonymous
alright

Looking for something else?

Not the answer you are looking for? Search for more explanations.