anonymous
  • anonymous
If θ is drawn in standard position, find its reference angle from θ = − 6π/8
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
DebbieG
  • DebbieG
That wording is a big odd, I'm assuming that θ = − 6π/8 ? And we want the reference angle? (And I'm not sure why that isn't fully reduced...??) But anyway, the reference angle is the angle between the terminal side of θ, and the x-axis (always a positive, acute angle) |dw:1378257497388:dw|
anonymous
  • anonymous
So the answer would be 2pi/8 or 1pi/4 depending on if they simplify or not?
DebbieG
  • DebbieG
Right. I would never say \(2\pi/8\).... I would expect my students to fully simplify. But it is the correct angle, reduced or not. :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.