anonymous
  • anonymous
Yvette has 5 more nickels than dimes. If the value of her money is $1.30, how many coins of each kind does she have?
Mathematics
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@gypsy1274 help me please?
anonymous
  • anonymous
Do you know how to solve systems of equations?
anonymous
  • anonymous
Yes I do

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anonymous
  • anonymous
@gypsy1274
anonymous
  • anonymous
No need to tag me, after I post a response, I will get a notification whenever another response is posted. nickels + dimes = 1.30 The second equation will need to include the values of those coins. Give it a try.
anonymous
  • anonymous
I'm still a bit confused on this so far I got $1.05
anonymous
  • anonymous
Umm @gypsy1274 ?
anonymous
  • anonymous
What is $1.05? What was the second equation?
anonymous
  • anonymous
Well I did $0.25+x=$1.50
anonymous
  • anonymous
Brain went dead....rebooting.....
anonymous
  • anonymous
anonymous
  • anonymous
My train of thought derailed, let me get it back on track.....
anonymous
  • anonymous
Yvette has 5 more nickels than dimes. If the value of her money is $1.30, how many coins of each kind does she have? \(n=d+5\) because there are five more nickels than dimes.
anonymous
  • anonymous
\(0.05n+0.10d=1.30\) because the value of the nickels plus dimes equals $1.30 Train is back on the rails now, sorry for the delay folks....
anonymous
  • anonymous
It's fine I guess I just want to figure this problem out because I have more HW to do for other classes
anonymous
  • anonymous
Do you understand these equations and where they came from? I'm sure they are correct this time, just verified it.
anonymous
  • anonymous
Since it says "5 more nickels" doesn't that mean it'll be 0.25 because your adding all the dimes together?
anonymous
  • anonymous
5 nickels are $0.25, that's true, but in that sentence, they are talking about the number of the coins not the values. The number of nickels equals the number of dimes plus five.
anonymous
  • anonymous
How do I know what to plug in in n and d ?
anonymous
  • anonymous
You don't plug in, you solve for them. \(n=d+5\) is already solved for n so plug \(d+5\) in for n in the other equation: \(0.5n+0.1d=1.30 \implies 0.5(d+5)+0.1d=1.30\)
anonymous
  • anonymous
I know you're trying to help me but your explaining it very good
anonymous
  • anonymous
I mean your not explaining it good my bad lol
anonymous
  • anonymous
@DebbieG - Perhaps you can try?
anonymous
  • anonymous
@e.mccormick I'm confusing this poor student, maybe you could help clarify?
anonymous
  • anonymous
@gypsy1274 thanks for trying though(: I appreciate it
e.mccormick
  • e.mccormick
Yah, I would do it with one equation. You have Dimes x and nickles x+5. Then, when you add those up with the proper value assigned you get 1.3.
anonymous
  • anonymous
What do you mean "add those up with the proper value"?
e.mccormick
  • e.mccormick
A dime is not just a word. It is a decimal value. =)
e.mccormick
  • e.mccormick
There is no reason for n or d because those have values. There is a count relationship between them. That count is a variable. So there are x dimes and x+5 nickles.
anonymous
  • anonymous
It still doesn't make much sence, my bad
e.mccormick
  • e.mccormick
If I said I had 72 dimes, you would instanly know I had $7.20. Right?
anonymous
  • anonymous
Yes
e.mccormick
  • e.mccormick
But why would you know?
anonymous
  • anonymous
Bc if I multiply 0.72 and 10 I get 7.20
e.mccormick
  • e.mccormick
Why .72? I had 72, not 72% of a dime.
anonymous
  • anonymous
Bc 72 dimes is written like that in decimal point
e.mccormick
  • e.mccormick
Yes. A dime is ten cents, or $0.10, and 72\(\times\)$0.10. Similarly, a nickle is five cents or $0.05. All I am saying is use that knowledge in the setup of the problem.
anonymous
  • anonymous
Would it be 0.10(5)+d=1.30
e.mccormick
  • e.mccormick
Not sure how you got there, but it is progress! That is one equation with one unknown, which is great. It is just not the right equation.
e.mccormick
  • e.mccormick
If I try and find d dimes and n nickles, I have to do two equations in two unknowns. But, if I restate the question this way: Yvette has 5 more $0.05 than $0.10. If the value of her money is $1.30, how many coins of each kind does she have? Can you do it in one unknown?
anonymous
  • anonymous
Ughhhhhhh!!!
anonymous
  • anonymous
I honestly have no clue right ow I have more HW to do still
e.mccormick
  • e.mccormick
As I said before, the dimes is the unknown. That means $0.10x must be part of this.
anonymous
  • anonymous
0.10(5)
e.mccormick
  • e.mccormick
I already gave you the dimes part. 0.10x. You need the nickles part.
e.mccormick
  • e.mccormick
How many nickles does it say she has? How would you write that if the number of dimes in the unknown?
anonymous
  • anonymous
$0.10x+$0.05y=$1.30
e.mccormick
  • e.mccormick
The problem with that is that it has two variables. So you need to get y in terms of x using a second formula. If x is the number of dimes, what is y in terms of x?
anonymous
  • anonymous
The number of nickels
e.mccormick
  • e.mccormick
That is y in terms of y. You need y in terms of x. Here is a huge clue. Take the first sentence. Replace dimes with x and nickles with y.
anonymous
  • anonymous
$0.05x+$0.10y=$1.50
e.mccormick
  • e.mccormick
That is completely wrong. Stick with $0.10x+$0.05y=$1.30. It is correct. But you need a second equation. Yvette has 5 more nickels than dimes. Yvette has 5 more y than x. What is that line, and JUST that line, as a mathematical formula?
anonymous
  • anonymous
An equation ill say
e.mccormick
  • e.mccormick
Let me go completely sideways for a second to show an example using similar language. If I have three pears and four apples, I have seven fruit. So: 3p+4a=7f. But what if I said it differently? I have one more apples than pears, and I have three pears. Then: ?a = 3p+1 The critical part is: a=p+1 Saying some more this than that means: that = this + some.
anonymous
  • anonymous
$0.05+0.10x=$1.30 ?
e.mccormick
  • e.mccormick
The $1.30 is not involved in the second equation. Just x, y, and some number creating a relationship between x and y. x being the number of dimes, y being the number of nickles, and the line: Yvette has 5 more nickels than dimes. Telling you all you need to know about that relationship.
e.mccormick
  • e.mccormick
They give you four numbers in this equation: Nickle, AKA:$0.05 Dime, AKA: $0.10 Total $1.30 and 5. You took it with two unknowns, number of nickles y and number of dimes x. OK. To do two equations, they must both use x and y. However, the goal is to break up the rest of the information. The first equation you did is fine. $0.10x+$0.05y=$1.30 It uses both x and y as required. It also uses $0.10, $0.05, and $1.30. Therefore your second equation can NOT use those or it is not generating new information. That leaves you with an equation involving: x, y, and 5. They tell you how to use 5 when they say: Yvette has 5 more nickels than dimes. So what is the equation?

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