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@gypsy1274 help me please?
Do you know how to solve systems of equations?
Yes I do
No need to tag me, after I post a response, I will get a notification whenever another response is posted. nickels + dimes = 1.30 The second equation will need to include the values of those coins. Give it a try.
I'm still a bit confused on this so far I got $1.05
Umm @gypsy1274 ?
What is $1.05? What was the second equation?
Well I did $0.25+x=$1.50
Brain went dead....rebooting.....
My train of thought derailed, let me get it back on track.....
Yvette has 5 more nickels than dimes. If the value of her money is $1.30, how many coins of each kind does she have? \(n=d+5\) because there are five more nickels than dimes.
\(0.05n+0.10d=1.30\) because the value of the nickels plus dimes equals $1.30 Train is back on the rails now, sorry for the delay folks....
It's fine I guess I just want to figure this problem out because I have more HW to do for other classes
Do you understand these equations and where they came from? I'm sure they are correct this time, just verified it.
Since it says "5 more nickels" doesn't that mean it'll be 0.25 because your adding all the dimes together?
5 nickels are $0.25, that's true, but in that sentence, they are talking about the number of the coins not the values. The number of nickels equals the number of dimes plus five.
How do I know what to plug in in n and d ?
You don't plug in, you solve for them. \(n=d+5\) is already solved for n so plug \(d+5\) in for n in the other equation: \(0.5n+0.1d=1.30 \implies 0.5(d+5)+0.1d=1.30\)
I know you're trying to help me but your explaining it very good
I mean your not explaining it good my bad lol
@DebbieG - Perhaps you can try?
@e.mccormick I'm confusing this poor student, maybe you could help clarify?
@gypsy1274 thanks for trying though(: I appreciate it
Yah, I would do it with one equation. You have Dimes x and nickles x+5. Then, when you add those up with the proper value assigned you get 1.3.
What do you mean "add those up with the proper value"?
A dime is not just a word. It is a decimal value. =)
There is no reason for n or d because those have values. There is a count relationship between them. That count is a variable. So there are x dimes and x+5 nickles.
It still doesn't make much sence, my bad
If I said I had 72 dimes, you would instanly know I had $7.20. Right?
But why would you know?
Bc if I multiply 0.72 and 10 I get 7.20
Why .72? I had 72, not 72% of a dime.
Bc 72 dimes is written like that in decimal point
Yes. A dime is ten cents, or $0.10, and 72\(\times\)$0.10. Similarly, a nickle is five cents or $0.05. All I am saying is use that knowledge in the setup of the problem.
Would it be 0.10(5)+d=1.30
Not sure how you got there, but it is progress! That is one equation with one unknown, which is great. It is just not the right equation.
If I try and find d dimes and n nickles, I have to do two equations in two unknowns. But, if I restate the question this way: Yvette has 5 more $0.05 than $0.10. If the value of her money is $1.30, how many coins of each kind does she have? Can you do it in one unknown?
I honestly have no clue right ow I have more HW to do still
As I said before, the dimes is the unknown. That means $0.10x must be part of this.
I already gave you the dimes part. 0.10x. You need the nickles part.
How many nickles does it say she has? How would you write that if the number of dimes in the unknown?
The problem with that is that it has two variables. So you need to get y in terms of x using a second formula. If x is the number of dimes, what is y in terms of x?
The number of nickels
That is y in terms of y. You need y in terms of x. Here is a huge clue. Take the first sentence. Replace dimes with x and nickles with y.
That is completely wrong. Stick with $0.10x+$0.05y=$1.30. It is correct. But you need a second equation. Yvette has 5 more nickels than dimes. Yvette has 5 more y than x. What is that line, and JUST that line, as a mathematical formula?
An equation ill say
Let me go completely sideways for a second to show an example using similar language. If I have three pears and four apples, I have seven fruit. So: 3p+4a=7f. But what if I said it differently? I have one more apples than pears, and I have three pears. Then: ?a = 3p+1 The critical part is: a=p+1 Saying some more this than that means: that = this + some.
The $1.30 is not involved in the second equation. Just x, y, and some number creating a relationship between x and y. x being the number of dimes, y being the number of nickles, and the line: Yvette has 5 more nickels than dimes. Telling you all you need to know about that relationship.
They give you four numbers in this equation: Nickle, AKA:$0.05 Dime, AKA: $0.10 Total $1.30 and 5. You took it with two unknowns, number of nickles y and number of dimes x. OK. To do two equations, they must both use x and y. However, the goal is to break up the rest of the information. The first equation you did is fine. $0.10x+$0.05y=$1.30 It uses both x and y as required. It also uses $0.10, $0.05, and $1.30. Therefore your second equation can NOT use those or it is not generating new information. That leaves you with an equation involving: x, y, and 5. They tell you how to use 5 when they say: Yvette has 5 more nickels than dimes. So what is the equation?