anonymous
  • anonymous
Can a single ordered pair be a function?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
i want to say no
anonymous
  • anonymous
That's what I thought but I wasn't sure because they question is worded as follows: Consider the relation {(3,4)} which consists of a single ordered pair. Any set of one or more ordered pairs is a relation. Thus every function is a relation but not every relation is a function. Is this relation a function? What is its domain?
anonymous
  • anonymous
@phi

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anonymous
  • anonymous
|dw:1378258877057:dw|
anonymous
  • anonymous
welll its arguable
anonymous
  • anonymous
Right but it's not a straight line it is just one ordered pair.
anonymous
  • anonymous
I can't tell....
anonymous
  • anonymous
well after googling, i guess you can consider it a function? a constant function f(x) = c with a domain of a single point
anonymous
  • anonymous
http://answers.yahoo.com/question/index?qid=20090917080036AAaW9v6
anonymous
  • anonymous
Okay. Thanks. I appreciate your help. :)
anonymous
  • anonymous
sorry, i tried
phi
  • phi
I never thought about this, but I would say yes The requirement for being a function is to be a "well-behaved" relation Any set of one or more ordered pairs is a relation. So one ordered pair is a relation. A well-behaved relation means given an x, we get only and exactly one y which is true for one ordered pair. So the ordered pair (x0,y0) meets the criteria of being a well-behaved relation, which makes it a function, with domain of one value x0 and a range of one value, y0

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