• anonymous
A scientist performs an experiment on an unknown element. She finds that the element forms an ionic bond with beryllium (Be) but not with lithium (Li). She concludes that the unknown element must belong in group 2 of the periodic table. State whether or not you think this result supports her conclusion, and why.
  • Stacey Warren - Expert
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  • jamiebookeater
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  • anonymous
i think this result doesn't supports her conclusion.. bcz ionic bond always forms between cation(metals) and anions(nonmetals) and group II elements are usually cations if an element forms ionic bond with Be which is from IIA group .. i can't be from IIA group... it must be an anion .. (..m nt sure ) @aaronq wt u say?
  • aaronq
i agree, it can't be from group 2 because cations can't bind because of repulsion. If it forms a bond with \(Be^{2+}\) but not \(Li^+\), then you can speculate that it's from group 6a, which would be a 2- anion (e.g. \(O^{-2}\)), or two -1 charged anions (\(BeA_2\)), then it could be from group 7.

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