anonymous
  • anonymous
An airplane if flying at an airspeed of 510 km/hr in a wind blowing at 60 km/hr toward the southeast. In what direction should the plan head to end up going due east?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
@satellite73
DDCamp
  • DDCamp
|dw:1378265530633:dw| Do you know how to find the ?°
anonymous
  • anonymous
Um, it should be arctan of 60/510?

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anonymous
  • anonymous
@DDCamp
anonymous
  • anonymous
use sine rule
anonymous
  • anonymous
How would that look?
anonymous
  • anonymous
you can't use SOHCAHTOA because it's not a right triangle \[\frac{sinA}{a} = \frac{sinB}{b} = \frac{sinC}{c}\] |dw:1378267042664:dw|
anonymous
  • anonymous
so then I am seeing\[\frac{ \sin(45) }{ 510 } = \frac{ \sin(x) }{ 60 }\]
anonymous
  • anonymous
@nphuongsun93
anonymous
  • anonymous
yes
anonymous
  • anonymous
I am getting 0.083 as an answer. Can you verify please @nphuongsun93
anonymous
  • anonymous
are you in degree mode? i got 4.77 degree as answer
anonymous
  • anonymous
Yes, I was in degree mode. Should I have been in radians?
anonymous
  • anonymous
nah should be degree. sin (45degree) /510 = 0.00138648 then * 60 = 0.083189 then arcsin (0.083189) = 4.77 degree
anonymous
  • anonymous
So how should I go about solving for the airplane's speed relative to the ground?
anonymous
  • anonymous
oh.. i was only solving the triangle drawn above, didn't even read the question
anonymous
  • anonymous
i don't really understand "going due east" mean, if possible can you draw which angle are we supposed to find?
anonymous
  • anonymous
It was to find the length of little c in DDCamp's picture up above. Since we found two angles now we need to find the bottom length in his drawing.
anonymous
  • anonymous
ah, with 2 angles out of 3, can you find the last angle?
anonymous
  • anonymous
It should be 130.23
anonymous
  • anonymous
yep, then use sin rule to find the last side
anonymous
  • anonymous
I'm seeing 550.64
anonymous
  • anonymous
yes

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