anonymous
  • anonymous
How do I use the square root method for this equation: (2y+3)^2=9
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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raffle_snaffle
  • raffle_snaffle
sqrt both sides
raffle_snaffle
  • raffle_snaffle
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anonymous
  • anonymous
The answers in my book are -3 and 0. I can get 0 just fine but I'm struggling to see how to find -3 as an answer can someone show the work as to how to get -3?

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campbell_st
  • campbell_st
if you take the square root of both sides of the equation you get \[2y + 3 = \pm 3\] which means you have 2 equations solve 2y + 3 = 3 and 2y + 3 = -3 hope this helps
anonymous
  • anonymous
Ah I forgot the +/- step thanks a bunch Campbell_St.

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