samigupta8
  • samigupta8
two particles P and Q of masses 5kg and 3kg respectively are attached to the ends of a string passing over a smooth pulley fixed to the ceiling of a lift.For a man inside the lift the acceleration of the system is 2g/7.When the acceleration of the lift is doubled in magnitude,find the new acceleration of the system
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
draw a figure!
samigupta8
  • samigupta8
|dw:1378302290357:dw|
anonymous
  • anonymous
and the whole system is inside an elevator.. accelerating in some direction.. lets say a .. so try to find the acceleration of 5kg and 3kg?!

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
in terms of a
samigupta8
  • samigupta8
if i cnsider rightly of the matter then i assume dat we can take the acceleration of 5 kg body downwards and that of 3 kg upward
anonymous
  • anonymous
ok do that.. lets do that.. forget about elevator.. just imagine the system.. now let go of it.. find out what is the acceleration of it?
samigupta8
  • samigupta8
a=5/2
anonymous
  • anonymous
u mean 5/2 g?
samigupta8
  • samigupta8
no it's simply 5/2
anonymous
  • anonymous
i am understanding how did you get that?!
anonymous
  • anonymous
not*
anonymous
  • anonymous
oh ok ok.. u took g = 10 !!
samigupta8
  • samigupta8
r u getting some another ans
anonymous
  • anonymous
wait wait.. i don't think you can do it that way.. i mean considering the lift to be at rest and then considering the acceelration of the elevator.. lemme try doing it first!!
samigupta8
  • samigupta8
okk....
anonymous
  • anonymous
i got the answer.. but i m not sure.. do you have the answer with u?!..
samigupta8
  • samigupta8
yaa
samigupta8
  • samigupta8
u telll u r ans
anonymous
  • anonymous
is it 9g/28?
samigupta8
  • samigupta8
yaa it's correct bt how did u get dat
anonymous
  • anonymous
ok.. then my logic is right.. lemme make a drawing for you!! igve me 5 mins!
samigupta8
  • samigupta8
ohkk...
anonymous
  • anonymous
See the drawing.. and tell me.. if u understand the logic!
1 Attachment
anonymous
  • anonymous
all u gotta do now is solve to get a (the acceleration of the elevator)
samigupta8
  • samigupta8
bt why you hve considered only the upward acceleration of lift
anonymous
  • anonymous
lift is either going up or down.. i randomly chose it as up!..
samigupta8
  • samigupta8
and why the apparent weight is m(g+a)
anonymous
  • anonymous
ok .. its not required to do it that way.. just look at this drawing
1 Attachment
anonymous
  • anonymous
now can you develop equations for each mass.. using that diagram?!
samigupta8
  • samigupta8
i m not getting it
samigupta8
  • samigupta8
a=49/20 if i m taking g=9.8
anonymous
  • anonymous
no.. i developed one equation for you.. check this
1 Attachment
anonymous
  • anonymous
does that make sense?!
samigupta8
  • samigupta8
do u want to say dat 2nd equation will be 3g-T=3(2g/7-a)
anonymous
  • anonymous
no.. thats wrong.. 3g is down.. so its negative.. T is up.. so its positive ..
samigupta8
  • samigupta8
hey why i m getting value of a=-10g/7
anonymous
  • anonymous
u should get it to be just g/7.. i told you .. ur equation is wrong.. the equation should be -3g+T = 3(2g/7 +a )
samigupta8
  • samigupta8
i got upto dat
samigupta8
  • samigupta8
bt how r u getting your acceleration is 9g/28
anonymous
  • anonymous
.. well.. the question is.. what happens to the acceleration of the system.. when the lift is accelerating twice the value.. which means now.. a = 2 previous value .. so a = 2(g/7) since now a is given.. find the acceleration of the system!!
anonymous
  • anonymous
1 Attachment
samigupta8
  • samigupta8
okkk .......thankuu...very much
anonymous
  • anonymous
no problem :)!!

Looking for something else?

Not the answer you are looking for? Search for more explanations.