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draw a figure!
and the whole system is inside an elevator.. accelerating in some direction.. lets say a .. so try to find the acceleration of 5kg and 3kg?!
in terms of a
if i cnsider rightly of the matter then i assume dat we can take the acceleration of 5 kg body downwards and that of 3 kg upward
ok do that.. lets do that.. forget about elevator.. just imagine the system.. now let go of it.. find out what is the acceleration of it?
u mean 5/2 g?
no it's simply 5/2
i am understanding how did you get that?!
oh ok ok.. u took g = 10 !!
r u getting some another ans
wait wait.. i don't think you can do it that way.. i mean considering the lift to be at rest and then considering the acceelration of the elevator.. lemme try doing it first!!
i got the answer.. but i m not sure.. do you have the answer with u?!..
u telll u r ans
is it 9g/28?
yaa it's correct bt how did u get dat
ok.. then my logic is right.. lemme make a drawing for you!! igve me 5 mins!
all u gotta do now is solve to get a (the acceleration of the elevator)
bt why you hve considered only the upward acceleration of lift
lift is either going up or down.. i randomly chose it as up!..
and why the apparent weight is m(g+a)
now can you develop equations for each mass.. using that diagram?!
i m not getting it
a=49/20 if i m taking g=9.8
does that make sense?!
do u want to say dat 2nd equation will be 3g-T=3(2g/7-a)
no.. thats wrong.. 3g is down.. so its negative.. T is up.. so its positive ..
hey why i m getting value of a=-10g/7
u should get it to be just g/7.. i told you .. ur equation is wrong.. the equation should be -3g+T = 3(2g/7 +a )
i got upto dat
bt how r u getting your acceleration is 9g/28
.. well.. the question is.. what happens to the acceleration of the system.. when the lift is accelerating twice the value.. which means now.. a = 2 previous value .. so a = 2(g/7) since now a is given.. find the acceleration of the system!!
okkk .......thankuu...very much
no problem :)!!