anonymous
  • anonymous
given a plane 2x-3y+5z-10=0 and point (-1,7,4) find a line parallel to the plane and passes through that point. i know the line equation needs a point and a direction. i have the point. as for the direction, it should be orthogonal to the normal of the plane, which is (2, -3, 5). two vectors are orthogonal if their dot product is zero. idk how to go from here. help !
Calculus1
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Luigi0210
  • Luigi0210
This isn't Calculus one is it? xD
anonymous
  • anonymous
(:
zpupster
  • zpupster
http://math.stackexchange.com/questions/477885/find-an-equation-for-the-line-that-is-parallel-to-the-plane-2x-3y-5z-10 there is a fine discussion and solution to your problem here. good luck

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anonymous
  • anonymous
yes i saw that but i am confused at the part where (2,-3,5) . (x,y,z) = 0 like idk how to get xyz. do i just choose any points?
zpupster
  • zpupster
Since 2x−3y+5z−c=0 will be parallel, we can sub in (−1,7,4) to get a c value of c=2(−1)−3(7)+5(4)=−3 , leaving us with the plane: 2x−3y+5z+3=0
zpupster
  • zpupster
follow the along with the bottom answer.
anonymous
  • anonymous
thanks !

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