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draw a graph of the function and indicate the average value \[f(x)=x ^{3}-5x ^{2}+10; \left[ 0,4 \right]\]

Mathematics
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average value is \[\frac{f(4)-f(0)}{4-0}\]
don't I use the anti-derivative of the function?
oh i see you want \[\frac{1}{4}\int_0^4(x^3-5x+10)dx\]

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Other answers:

aka "mean value" right
yes I believe that is what the question calls for
ok the "anti derivative" is not too bad because this is a polynomial it is \[\frac{x^4}{4}-\frac{5x^2}{2}+10x\]
(5x^3)/3 right
plug in 4 ignore 0 because that just gives you 0 then divide by 4
right i did all that. i got approx. -.75. does that seem correct?
it is \(-5x\) or \(-5x^2\) ?
-5x^2
oooh ok
then no it is \(-\frac{2}{3}\)
ok i get that. But how would they go on the graph. Could you give me a crude drawing?
here is a nice drawing http://www.wolframalpha.com/input/?i=x^3-5x^2%2B10+domain+0..4
and the average value represented on the graph would just be a straight line at -2/3?
that i do not know sorry
ok thank you

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