## MATTW20 one year ago draw a graph of the function and indicate the average value $f(x)=x ^{3}-5x ^{2}+10; \left[ 0,4 \right]$

1. satellite73

average value is $\frac{f(4)-f(0)}{4-0}$

2. MATTW20

don't I use the anti-derivative of the function?

3. satellite73

oh i see you want $\frac{1}{4}\int_0^4(x^3-5x+10)dx$

4. satellite73

aka "mean value" right

5. MATTW20

yes I believe that is what the question calls for

6. satellite73

ok the "anti derivative" is not too bad because this is a polynomial it is $\frac{x^4}{4}-\frac{5x^2}{2}+10x$

7. MATTW20

(5x^3)/3 right

8. satellite73

plug in 4 ignore 0 because that just gives you 0 then divide by 4

9. MATTW20

right i did all that. i got approx. -.75. does that seem correct?

10. satellite73

it is $$-5x$$ or $$-5x^2$$ ?

11. MATTW20

-5x^2

12. satellite73

oooh ok

13. satellite73

then no it is $$-\frac{2}{3}$$

14. MATTW20

ok i get that. But how would they go on the graph. Could you give me a crude drawing?

15. satellite73

here is a nice drawing http://www.wolframalpha.com/input/?i=x^3-5x^2%2B10+domain+0..4

16. MATTW20

and the average value represented on the graph would just be a straight line at -2/3?

17. satellite73

that i do not know sorry

18. MATTW20

ok thank you