anonymous
  • anonymous
Find the area of ABCD and solve for x.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
@paul1231
anonymous
  • anonymous
is AB= 5?

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anonymous
  • anonymous
yes
anonymous
  • anonymous
do you know how to find the area of a parallelogram is?
anonymous
  • anonymous
is it A= bh?
anonymous
  • anonymous
so A= 30 units^2?
anonymous
  • anonymous
yeah A=(4)(7.5) = 30 units
anonymous
  • anonymous
Okay but how do i find x?
anonymous
  • anonymous
|dw:1378306016319:dw|
anonymous
  • anonymous
but BC = AD = 7.5 and AB = CD = 5
anonymous
  • anonymous
|dw:1378306185781:dw|
anonymous
  • anonymous
did you understand how we got those values
anonymous
  • anonymous
kind of....
anonymous
  • anonymous
opposite sides of a parallelogram are equal right?
anonymous
  • anonymous
oh yeah
anonymous
  • anonymous
ok so at ---> end we have a right angle triangle can you find the third side of a RAT if two sides are given
anonymous
  • anonymous
what does RAT stand for... Right Angle Triangle?
anonymous
  • anonymous
yes
anonymous
  • anonymous
yes by the pythagorean theorem
anonymous
  • anonymous
yep so we have a right angled triangle in the diagram right? with sides x 4 5 use pythagorean theorm to find x
anonymous
  • anonymous
|dw:1378306591697:dw|
anonymous
  • anonymous
yea thats what i got 3 for the side to the right
anonymous
  • anonymous
|dw:1378310207280:dw|
anonymous
  • anonymous
yep so we almost have the image figured out
anonymous
  • anonymous
do you know trignometry?
anonymous
  • anonymous
yes
anonymous
  • anonymous
sin cos and tan right
anonymous
  • anonymous
|dw:1378306752206:dw|
anonymous
  • anonymous
huh?
anonymous
  • anonymous
so if that is angle theta what would be cos theta =?
anonymous
  • anonymous
what is theta???
anonymous
  • anonymous
sin theta cos theta and tan theta right?
anonymous
  • anonymous
i know sin cos and tan idk what the theta is
anonymous
  • anonymous
\[\cos \theta =?\]
anonymous
  • anonymous
that symbol?
anonymous
  • anonymous
no i havent used that symbol yet.
anonymous
  • anonymous
oh nevermind then
anonymous
  • anonymous
|dw:1378310516284:dw|
anonymous
  • anonymous
is that side i pointed at in the drawing 5
anonymous
  • anonymous
?
anonymous
  • anonymous
why do you think its 5
anonymous
  • anonymous
it looks equal...
anonymous
  • anonymous
nevermind though there is no way to prove that.
anonymous
  • anonymous
haha yep you need to prove everything you write
anonymous
  • anonymous
do you know any theorms to find the remaining sides
anonymous
  • anonymous
|dw:1378310699129:dw|
anonymous
  • anonymous
can i use sin 90? to find x?
anonymous
  • anonymous
that isnt a 90 degree
anonymous
  • anonymous
It is
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
oh yeah i just noticed but you cannot use sin 90
anonymous
  • anonymous
it muse be one of the other angles
anonymous
  • anonymous
|dw:1378307371533:dw|
anonymous
  • anonymous
do you know the definition of sin
anonymous
  • anonymous
opp./adj.
anonymous
  • anonymous
sin = opp/hyp cos = adj / hyp tan = opp / adj
anonymous
  • anonymous
|dw:1378307503119:dw|
anonymous
  • anonymous
do you know how to find the angle x
anonymous
  • anonymous
tan x = 4/3
anonymous
  • anonymous
yep so tan x = 4/3 tan x =1.33333 x= arctan 1.33333 x=53.13 degrees
anonymous
  • anonymous
|dw:1378307881186:dw|
anonymous
  • anonymous
how did you get x = arctan 1.33333
anonymous
  • anonymous
shouldnt it be x= 1.333/tan
anonymous
  • anonymous
if you have sin x = some value then you can multiply both sides by arcsin to get arcsin (sin x) = arcsin(some value) but arcsin ( sinx) = x x=arcsin(some value)
anonymous
  • anonymous
it works similar for arccos and arctan
anonymous
  • anonymous
no in the case of sin cos and tan you cant divide it that way
anonymous
  • anonymous
if we have 2x = 3 then x = 2/3 which is nothing but x = 3*1/2 here 1/2 is the INVERSE of 2 right? in case of sin cos and tan arcsin arccos arctan are the inverse
anonymous
  • anonymous
ohhhh yeah ....
anonymous
  • anonymous
did you really understand what i just said
anonymous
  • anonymous
you could have said the inverse
anonymous
  • anonymous
haha so you know what inverse sin cos tan does?
anonymous
  • anonymous
yes.
anonymous
  • anonymous
sin 30 degrees= 1/2 arcsin(1/2) = 30 degrees right?
anonymous
  • anonymous
yes i get it now
anonymous
  • anonymous
so anyway now you can use sin 53.13 = opp/hyp sin 53.13 = x/7.5 (sin 53.13) * 7.5 = x 0.79999 * 7.5 = x 5.99999 = x aproximately x=6
anonymous
  • anonymous
will you be able do to this in the test
anonymous
  • anonymous
yes thank you so much
anonymous
  • anonymous
its okay see you later
anonymous
  • anonymous
it should be sin 53.123 though not 53.13
anonymous
  • anonymous
i might have made a mistake but either way the result is approximately 6 so its alright

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