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is AB= 5?
do you know how to find the area of a parallelogram is?
is it A= bh?
so A= 30 units^2?
yeah A=(4)(7.5) = 30 units
Okay but how do i find x?
but BC = AD = 7.5 and AB = CD = 5
did you understand how we got those values
opposite sides of a parallelogram are equal right?
ok so at ---> end we have a right angle triangle can you find the third side of a RAT if two sides are given
what does RAT stand for... Right Angle Triangle?
yes by the pythagorean theorem
yep so we have a right angled triangle in the diagram right? with sides x 4 5 use pythagorean theorm to find x
yea thats what i got 3 for the side to the right
yep so we almost have the image figured out
do you know trignometry?
sin cos and tan right
so if that is angle theta what would be cos theta =?
what is theta???
sin theta cos theta and tan theta right?
i know sin cos and tan idk what the theta is
\[\cos \theta =?\]
no i havent used that symbol yet.
oh nevermind then
is that side i pointed at in the drawing 5
why do you think its 5
it looks equal...
nevermind though there is no way to prove that.
haha yep you need to prove everything you write
do you know any theorms to find the remaining sides
can i use sin 90? to find x?
that isnt a 90 degree
oh yeah i just noticed but you cannot use sin 90
it muse be one of the other angles
do you know the definition of sin
sin = opp/hyp cos = adj / hyp tan = opp / adj
do you know how to find the angle x
tan x = 4/3
yep so tan x = 4/3 tan x =1.33333 x= arctan 1.33333 x=53.13 degrees
how did you get x = arctan 1.33333
shouldnt it be x= 1.333/tan
if you have sin x = some value then you can multiply both sides by arcsin to get arcsin (sin x) = arcsin(some value) but arcsin ( sinx) = x x=arcsin(some value)
it works similar for arccos and arctan
no in the case of sin cos and tan you cant divide it that way
if we have 2x = 3 then x = 2/3 which is nothing but x = 3*1/2 here 1/2 is the INVERSE of 2 right? in case of sin cos and tan arcsin arccos arctan are the inverse
ohhhh yeah ....
did you really understand what i just said
you could have said the inverse
haha so you know what inverse sin cos tan does?
sin 30 degrees= 1/2 arcsin(1/2) = 30 degrees right?
yes i get it now
so anyway now you can use sin 53.13 = opp/hyp sin 53.13 = x/7.5 (sin 53.13) * 7.5 = x 0.79999 * 7.5 = x 5.99999 = x aproximately x=6
will you be able do to this in the test
yes thank you so much
its okay see you later
it should be sin 53.123 though not 53.13
i might have made a mistake but either way the result is approximately 6 so its alright