anonymous
  • anonymous
Find the sum of all real solutions of the equation x^2−16=3(x−4)^2.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Solve for x over the real numbers: x^2-16 = 3 (x-4)^2 Write the quadratic polynomial on the right hand side in standard form. Expand out terms of the right hand side: x^2-16 = 3 x^2-24 x+48 Move everything to the left hand side. Subtract 3 x^2-24 x+48 from both sides: -2 x^2+24 x-64 = 0 Factor the left hand side. The left hand side factors into a product with three terms: -2 (x-8) (x-4) = 0 Divide both sides by a constant to simplify the equation. Divide both sides by -2: (x-8) (x-4) = 0 Solve each term in the product separately. Split into two equations: x-8 = 0 or x-4 = 0 Look at the first equation: Solve for x. Add 8 to both sides: x = 8 or x-4 = 0 Look at the second equation: Solve for x. Add 4 to both sides: Answer: | | x = 8 or x = 4
anonymous
  • anonymous
\[\left( a-b \right)^{2}=a ^{2}+b ^{2}-2ab\]
anonymous
  • anonymous
\[ax ^{2}+bx+c=0\] sum of roots=-b/a

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
so the answer is 4 ?
anonymous
  • anonymous
let me check
anonymous
  • anonymous
x^2-16=3(x-4)^2 x^2-16=3(x^2-8x+16) 2x^2-24x+64=0 x^2-12x+32=0 sum of roots=-(-12)/1=12

Looking for something else?

Not the answer you are looking for? Search for more explanations.