samigupta8
  • samigupta8
two blocks of masses m1 and m2 are connected to each other through a light spring as shown in figure.If we push mass m1 with force F and cause acceleration a1 in mass m1 what will be the acceleration in m2?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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samigupta8
  • samigupta8
|dw:1378314556336:dw|
amistre64
  • amistre64
Force = mass x accel. a spring constant has a similar equation: F = -kx for some constant k, and i think x is a distance compressed?
amistre64
  • amistre64
combining the 2 would give us something like: accel = -kx/m

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amistre64
  • amistre64
but other than that, i dont really have time at the moment to focus better on it
samigupta8
  • samigupta8
but how will u find the value of kx
amistre64
  • amistre64
you have to keep it general since they really dont give you any values to play with
amistre64
  • amistre64
im thinking you would want to combine the force of the push with the force of the spring
samigupta8
  • samigupta8
yaaaa
amistre64
  • amistre64
|dw:1378316511593:dw|
amistre64
  • amistre64
not sure if the masses combine or not ...
samigupta8
  • samigupta8
i don't think they will
amistre64
  • amistre64
good luck with the rest of it :) I have to be going ..
anonymous
  • anonymous
spring force is internal force for system so both m1 and m2 have same accelaration a=f/(m1+m2)
samigupta8
  • samigupta8
no it's not the answer
theEric
  • theEric
@gyanu , is the force split into the acceleration of \(m_1\) and \(m_2\) and the compression of the spring?
anonymous
  • anonymous
here \[a _{1}=\frac{ f-kx }{ m _{1} }\] force on second mass is kx so \[a _{2}= \frac{ kx }{ m _{2} }\] using both equations \[a _{2}=\frac{ f-m _{1}a _{1} }{m _{2}}\]
anonymous
  • anonymous
is this your answer??
samigupta8
  • samigupta8
yaa bt how did u get it as a=f-kx/m1
anonymous
  • anonymous
@theEric no force does not split.On first mass two forces acting F and spring force and second mass only spring force acting.
samigupta8
  • samigupta8
ok...i got it myself....thankuu..so much
anonymous
  • anonymous
|dw:1378318029944:dw|
anonymous
  • anonymous
so F-kx=m1a1
theEric
  • theEric
Nice! Congrats! And cool, thanks!

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