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LaynaMae Group Title

Without any trolling . Can anyone help me figure this out ?

  • one year ago
  • one year ago

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  1. LaynaMae Group Title
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    • one year ago
  2. skullpatrol Group Title
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    Any ideas?

    • one year ago
  3. LaynaMae Group Title
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    Don't I have to replace f(x) with y or something ..? :c

    • one year ago
  4. skullpatrol Group Title
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    You have to understand what f(x) means, which is?

    • one year ago
  5. LaynaMae Group Title
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    Function notation ?

    • one year ago
  6. skullpatrol Group Title
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    Yes...but what does it say about x?

    • one year ago
  7. LaynaMae Group Title
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    Replace it with -1

    • one year ago
  8. skullpatrol Group Title
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    Yes, in your question do it first with the function g(-1)

    • one year ago
  9. LaynaMae Group Title
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    Wait so what am I doing ..? I'm sorry I don't understand any of this ..

    • one year ago
  10. skullpatrol Group Title
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    Start first within the innermost parentheses of $$\huge f(g(x))$$ and work towards the outermost parentheses ...

    • one year ago
  11. LaynaMae Group Title
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    I know that much I just don't know how to solve it or work it out

    • one year ago
  12. skullpatrol Group Title
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    |dw:1378321409759:dw|

    • one year ago
  13. LaynaMae Group Title
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    I thought so . But I wasn't sure if -1 went in g(x) ..

    • one year ago
  14. skullpatrol Group Title
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    Now what?

    • one year ago
  15. LaynaMae Group Title
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    Do we work out f(x) ..?

    • one year ago
  16. skullpatrol Group Title
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    Yes.

    • one year ago
  17. LaynaMae Group Title
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    Replace "x" with -1 ?

    • one year ago
  18. skullpatrol Group Title
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    We use the result from g(-1) in f. That is what f(g(x)) means...

    • one year ago
  19. LaynaMae Group Title
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    Okay so 2 then .

    • one year ago
  20. LaynaMae Group Title
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    That would be 5 then

    • one year ago
  21. skullpatrol Group Title
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    f(x)=5x-10

    • one year ago
  22. LaynaMae Group Title
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    Yes , isn't the answer 5 ?

    • one year ago
  23. skullpatrol Group Title
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    How?

    • one year ago
  24. LaynaMae Group Title
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    |dw:1378321832200:dw|

    • one year ago
  25. skullpatrol Group Title
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    Excuse me? Are you trying to troll me with $$\huge5(2)=25$$

    • one year ago
  26. LaynaMae Group Title
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    No ?? I thought that's that you had to do .. Sorry ...

    • one year ago
  27. LaynaMae Group Title
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    what *

    • one year ago
  28. skullpatrol Group Title
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    |dw:1378322275977:dw|

    • one year ago
  29. LaynaMae Group Title
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    I already warned you that I didn't know how to do any of this .

    • one year ago
  30. LaynaMae Group Title
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    Ok I know .

    • one year ago
  31. skullpatrol Group Title
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    so what is 5*2=?

    • one year ago
  32. LaynaMae Group Title
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    25 I know . I understand that .

    • one year ago
  33. LaynaMae Group Title
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    I mean 10 sorry

    • one year ago
  34. skullpatrol Group Title
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    I just kidding about the trolling :D so what is your answer?

    • one year ago
  35. LaynaMae Group Title
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    Ok . It's 10

    • one year ago
  36. skullpatrol Group Title
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    correct your work please

    • one year ago
  37. LaynaMae Group Title
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    What ?

    • one year ago
  38. skullpatrol Group Title
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    |dw:1378322533506:dw|

    • one year ago
  39. LaynaMae Group Title
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    It's not worth correcting though , I already know the answer . So is 10 the answer to the entire question ?

    • one year ago
  40. LaynaMae Group Title
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    Or just for f(x)

    • one year ago
  41. skullpatrol Group Title
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    |dw:1378322646531:dw|

    • one year ago
  42. skullpatrol Group Title
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    f(g(x)) = 0 when x = -1

    • one year ago
  43. LaynaMae Group Title
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    Okay

    • one year ago
  44. LaynaMae Group Title
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    Okay thank you

    • one year ago
  45. skullpatrol Group Title
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    |dw:1378322937548:dw|

    • one year ago
  46. LaynaMae Group Title
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    What about this one ?

    • one year ago
  47. skullpatrol Group Title
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    What about it?

    • one year ago
  48. LaynaMae Group Title
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    Nevermind I'm just going to guess . I don't have enough time to work out all of these problems . Thanks for your help though .

    • one year ago
  49. skullpatrol Group Title
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    I can help if you want to learn :-)

    • one year ago
  50. skullpatrol Group Title
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    It is the same as the last one we did ...

    • one year ago
  51. skullpatrol Group Title
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    Just let x=15

    • one year ago
  52. LaynaMae Group Title
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    I do want to learn but I'm being timed . I'm taking a quiz . I don't have time to work out anything else ....

    • one year ago
  53. skullpatrol Group Title
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    start from the innermost function

    • one year ago
  54. LaynaMae Group Title
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    I tried working it out , is it 16 ? Yes or no :o

    • one year ago
  55. LaynaMae Group Title
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    Ugh .. That was my second choice -.-

    • one year ago
  56. skullpatrol Group Title
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    Go.od luck, come back and learn when you have time

    • one year ago
  57. LaynaMae Group Title
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    Okay

    • one year ago
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is replying to Can someone tell me what button the professor is hitting...

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