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anonymous

  • 3 years ago

Without any trolling . Can anyone help me figure this out ?

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  1. anonymous
    • 3 years ago
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  2. skullpatrol
    • 3 years ago
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    Any ideas?

  3. anonymous
    • 3 years ago
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    Don't I have to replace f(x) with y or something ..? :c

  4. skullpatrol
    • 3 years ago
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    You have to understand what f(x) means, which is?

  5. anonymous
    • 3 years ago
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    Function notation ?

  6. skullpatrol
    • 3 years ago
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    Yes...but what does it say about x?

  7. anonymous
    • 3 years ago
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    Replace it with -1

  8. skullpatrol
    • 3 years ago
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    Yes, in your question do it first with the function g(-1)

  9. anonymous
    • 3 years ago
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    Wait so what am I doing ..? I'm sorry I don't understand any of this ..

  10. skullpatrol
    • 3 years ago
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    Start first within the innermost parentheses of $$\huge f(g(x))$$ and work towards the outermost parentheses ...

  11. anonymous
    • 3 years ago
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    I know that much I just don't know how to solve it or work it out

  12. skullpatrol
    • 3 years ago
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    |dw:1378321409759:dw|

  13. anonymous
    • 3 years ago
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    I thought so . But I wasn't sure if -1 went in g(x) ..

  14. skullpatrol
    • 3 years ago
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    Now what?

  15. anonymous
    • 3 years ago
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    Do we work out f(x) ..?

  16. skullpatrol
    • 3 years ago
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    Yes.

  17. anonymous
    • 3 years ago
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    Replace "x" with -1 ?

  18. skullpatrol
    • 3 years ago
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    We use the result from g(-1) in f. That is what f(g(x)) means...

  19. anonymous
    • 3 years ago
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    Okay so 2 then .

  20. anonymous
    • 3 years ago
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    That would be 5 then

  21. skullpatrol
    • 3 years ago
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    f(x)=5x-10

  22. anonymous
    • 3 years ago
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    Yes , isn't the answer 5 ?

  23. skullpatrol
    • 3 years ago
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    How?

  24. anonymous
    • 3 years ago
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    |dw:1378321832200:dw|

  25. skullpatrol
    • 3 years ago
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    Excuse me? Are you trying to troll me with $$\huge5(2)=25$$

  26. anonymous
    • 3 years ago
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    No ?? I thought that's that you had to do .. Sorry ...

  27. anonymous
    • 3 years ago
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    what *

  28. skullpatrol
    • 3 years ago
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    |dw:1378322275977:dw|

  29. anonymous
    • 3 years ago
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    I already warned you that I didn't know how to do any of this .

  30. anonymous
    • 3 years ago
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    Ok I know .

  31. skullpatrol
    • 3 years ago
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    so what is 5*2=?

  32. anonymous
    • 3 years ago
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    25 I know . I understand that .

  33. anonymous
    • 3 years ago
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    I mean 10 sorry

  34. skullpatrol
    • 3 years ago
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    I just kidding about the trolling :D so what is your answer?

  35. anonymous
    • 3 years ago
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    Ok . It's 10

  36. skullpatrol
    • 3 years ago
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    correct your work please

  37. anonymous
    • 3 years ago
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    What ?

  38. skullpatrol
    • 3 years ago
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    |dw:1378322533506:dw|

  39. anonymous
    • 3 years ago
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    It's not worth correcting though , I already know the answer . So is 10 the answer to the entire question ?

  40. anonymous
    • 3 years ago
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    Or just for f(x)

  41. skullpatrol
    • 3 years ago
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    |dw:1378322646531:dw|

  42. skullpatrol
    • 3 years ago
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    f(g(x)) = 0 when x = -1

  43. anonymous
    • 3 years ago
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    Okay

  44. anonymous
    • 3 years ago
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    Okay thank you

  45. skullpatrol
    • 3 years ago
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    |dw:1378322937548:dw|

  46. anonymous
    • 3 years ago
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    What about this one ?

  47. skullpatrol
    • 3 years ago
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    What about it?

  48. anonymous
    • 3 years ago
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    Nevermind I'm just going to guess . I don't have enough time to work out all of these problems . Thanks for your help though .

  49. skullpatrol
    • 3 years ago
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    I can help if you want to learn :-)

  50. skullpatrol
    • 3 years ago
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    It is the same as the last one we did ...

  51. skullpatrol
    • 3 years ago
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    Just let x=15

  52. anonymous
    • 3 years ago
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    I do want to learn but I'm being timed . I'm taking a quiz . I don't have time to work out anything else ....

  53. skullpatrol
    • 3 years ago
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    start from the innermost function

  54. anonymous
    • 3 years ago
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    I tried working it out , is it 16 ? Yes or no :o

  55. anonymous
    • 3 years ago
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    Ugh .. That was my second choice -.-

  56. skullpatrol
    • 3 years ago
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    Go.od luck, come back and learn when you have time

  57. anonymous
    • 3 years ago
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    Okay

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