samigupta8
  • samigupta8
a block tied between two springs is in equilibrium.If upper spring is cut then the acceleration of the block just after cut is 6m/s^2 downwards.Now,if instead of upper spring lower spring is cut then the magnitude of acceleration of the block just after the cut will be (take g=10m/s^2)
Physics
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SOLVED
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chestercat
  • chestercat
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samigupta8
  • samigupta8
|dw:1378321195056:dw|
oOKawaiiOo
  • oOKawaiiOo
mg = -kx
samigupta8
  • samigupta8
i m asking abt the acceleration of the block just aftr the lower strig is cut

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oOKawaiiOo
  • oOKawaiiOo
ma= -kx -mg Find a, which is your acceleration
samigupta8
  • samigupta8
bt untill unless u don't know the value of x we cnnot find out wt is acceleration
oOKawaiiOo
  • oOKawaiiOo
You have to know the k constant of the spring, without it you cannot find acceleration.
samigupta8
  • samigupta8
exactly but as per question only we know the accelration of block when upper string is being cut
samigupta8
  • samigupta8
do u hve any idea how to solve such a ques
oOKawaiiOo
  • oOKawaiiOo
its usually given :/
samigupta8
  • samigupta8
oh reallyy i didn't know it
samigupta8
  • samigupta8
thanu so much for telling dat to me
anonymous
  • anonymous
In above problem springs are different so let spring constant of one is k1 and of other is k2. so at equilibrium k1x+k2x= mg so x=mg/(k1+k2)..........................................................(1) when upper spring is cut then force eqn is mg-k2x=ma1 here a1= 6m/s2 so above eqn become mg-k2x=6m............................................(2) now in second case lower spring is cut therefore force eqn is mg-k1x=ma2..............................................(3) Now by using above three eqns u will get a2=4m/s2
samigupta8
  • samigupta8
hey i think that the thir equation should be k1x-mg=ma2
anonymous
  • anonymous
no in both conditions acceleration always downward so all eqns are correct
anonymous
  • anonymous
put the value of x from eqn (1) to eqn (2) u will get a relation btw k1 and k2 as 2k1=3k2 now put the value of x and k2 in eqn (3) u will get the answer try is carefully.
samigupta8
  • samigupta8
hey i m getting k1 mg=6m(k1+k2)
samigupta8
  • samigupta8
but there is no k2 in 3rd equation as such
samigupta8
  • samigupta8
okk..i got it thanksss...

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