anonymous
  • anonymous
I need help with Interval notation
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Okay , what kind of help ?
theEric
  • theEric
Hi! Do you have some part of it in particular you need help with? Do you just want to understand it in general?
anonymous
  • anonymous
\[3/2 \ge x < \]

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More answers

anonymous
  • anonymous
0 at the end
theEric
  • theEric
So, you want to say that \(\frac{3}{2}\) is greater than or equal to \(x\), and \(x\) is less than \(0\)? So, \(\frac{3}{2}\ge x\) and \(x\lt0\)?
anonymous
  • anonymous
Yes
anonymous
  • anonymous
wait
anonymous
  • anonymous
\[3/2 \ge x > 0\]
theEric
  • theEric
I would try to visualize it on a number line quick. That usually helps. Okay, I have to draw the picture quick.
theEric
  • theEric
|dw:1378324975369:dw|
amistre64
  • amistre64
the hardest part tends to be in remembering which brackets to use
theEric
  • theEric
Oh, here's a link! http://www.mathsisfun.com/sets/intervals.html
amistre64
  • amistre64
think of the square bracket as an equal sign connected by a bar |dw:1378325178389:dw|
theEric
  • theEric
Now, in my picture, I drew the two inequalities. Where do they over lap? They overlap to the right of \(0\) up to where \(\frac{3}{2}\) is!
theEric
  • theEric
Haha, nice @amistre64 !
amistre64
  • amistre64
\[a\le x
amistre64
  • amistre64
its the only way i know to keeo track of all these notations :)
theEric
  • theEric
For that interval, \(\frac{3}{2}\ge x\gt0\), it starts just to the right of \(0\), so you want to NOT INCLUDE \(0\). You know? So you have to use a \((\).
anonymous
  • anonymous
So it's (3/2,0] ?
theEric
  • theEric
And your interval include everything between \(0\) and \(\frac{3}{2}\), and \(\frac{3}{2}\). Since in includes \(\frac{3}{2}\), you want to use \(]\).
theEric
  • theEric
@Juliaxo9 I think we always want the number on the left to be the lesser number, and the one on the right to be greater!
theEric
  • theEric
You go from \(0\) to \(\frac{3}{2}\), then!
anonymous
  • anonymous
[0, 3/2) ?
theEric
  • theEric
Close! So they're in the correct order! \(\frac{3}{2}\ge x\gt0\) Now look at the signs. \(x\gt0\), but not equal to \(0\). So, should you use \((\) to show "not equal," or \([\) to show "equal to."
theEric
  • theEric
?*
anonymous
  • anonymous
Sorry I went to eat
theEric
  • theEric
Haha, no problem!
anonymous
  • anonymous
(0, 3/2)
theEric
  • theEric
Okay, so, I'll just read what that says, and you tell me if it is correct. You are going from \(0\), but not including \(0\), to \(\frac{3}{2}\), but not including \(\frac{3}{2}\). So that's where \(x\) must be. Is that right?
theEric
  • theEric
Based on \(\frac{3}{2}\ge x\gt0\)?
anonymous
  • anonymous
Yes
theEric
  • theEric
It looks like \(\dfrac{3}{2}\) is greater than \(\sf or\ equal\ to\) \(x\), right?
theEric
  • theEric
\(\ge\)
theEric
  • theEric
\(\dfrac{3}{2}\ge x\) means \(\dfrac{3}{2} > x\) or \(\dfrac{3}{2}=x\) So, \(x\) can be \(\dfrac{3}{2}\), so you want to say that with a \(]\)! :)
theEric
  • theEric
So, \(\left(0,~\dfrac{3}{2}\right]\)
anonymous
  • anonymous
but I thought 3/2 is bigger so it's first
theEric
  • theEric
I think, with that interval notation, you want the smaller number on the left. \(\left( lesser,\ greater\right]\)
theEric
  • theEric
like \((-51,\ 10]\)
theEric
  • theEric
I have to go, but feel free to check out the link I posted! Take care!
anonymous
  • anonymous
Ohh! Ok!
anonymous
  • anonymous
Can you check few for me?
anonymous
  • anonymous
\[-4 < x < \]
anonymous
  • anonymous
4 at the end sorry
anonymous
  • anonymous
(-4,4) ?
anonymous
  • anonymous
@theEric
anonymous
  • anonymous
nvm got it thank you!!!
theEric
  • theEric
You are correct! :)
anonymous
  • anonymous
:)

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