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Falco276

  • 2 years ago

HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! The equation of a circle is shown below. (x -5)2 + (y + 2)2 = 64 The radius of the circle is ________ units. (No Multiple Choice)

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  1. Falco276
    • 2 years ago
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    @.Sam. @andriod09 @Gin_Ichimaru @ganeshie8 @Hunter15 @Creation @aaronq @lalokio

  2. Falco276
    • 2 years ago
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    @hba @Frostbite @Hero @lexi14 @phi @Meriam

  3. phi
    • 2 years ago
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    http://www.mathwarehouse.com/geometry/circle/equation-of-a-circle.php

  4. Falco276
    • 2 years ago
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    But what's the answer!?

  5. Falco276
    • 2 years ago
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    I'm confused!!!!!!!!!!!!

  6. anonymous
    • 2 years ago
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    \[(x-h)^2+(y-k)^2=r^2\] is the equation of a circle with radius \(r\) and center \((h,k)\)

  7. anonymous
    • 2 years ago
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    in your case \(r^2=64\) what is \(r\) ?

  8. Falco276
    • 2 years ago
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    And how do I translate that into the real equation?

  9. Falco276
    • 2 years ago
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    I actuall don't know what R is. :/

  10. anonymous
    • 2 years ago
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    \[(x-h)^2+(y-k)^2=r^2\\(x-5)^2+(y+2)^2=64\] look almost identical

  11. Falco276
    • 2 years ago
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    okay, so it's 64. Right?

  12. anonymous
    • 2 years ago
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    \(r^2\) is 64 but you are asked for the radius, which is \(r\) what number would you square to get 64?

  13. Falco276
    • 2 years ago
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    8?

  14. anonymous
    • 2 years ago
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    yes

  15. Falco276
    • 2 years ago
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    so that's the answer, right? 8?

  16. Falco276
    • 2 years ago
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    hello? :(

  17. anonymous
    • 2 years ago
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    yes

  18. Falco276
    • 2 years ago
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    okay, thanks. :)

  19. anonymous
    • 2 years ago
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    \(64=8^2\) so \(r=8\) yw

  20. Falco276
    • 2 years ago
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    thanks. :)

  21. Falco276
    • 2 years ago
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    Wait guys, I have another question. segment PR has an endpoint at (25, -5) and a midpoint of (18, -1). What is the value of the x-coordinate of the other endpoint?

  22. Falco276
    • 2 years ago
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    @satellite73 @Loser66 @geoffb

  23. Falco276
    • 2 years ago
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    (this one is also not multiple choice.)

  24. Loser66
    • 2 years ago
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    post at a new post, friend

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