anonymous
  • anonymous
I need help it says solve for w when the formula is p=4+2w I dont know what to do with the p
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
first, get the w term by itself. So move 4 over to the left hand side. Do you know how to do this?
anonymous
  • anonymous
|dw:1378328500676:dw|
anonymous
  • anonymous
that does not explain the steps of the problem....

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anonymous
  • anonymous
what I did I divide 2 on both sides and my answer I got is w=4/2
anonymous
  • anonymous
the first step: when you have p=4+2w, you first move the 4 over to the left hand side. you do this by subtracting. So your equation become p-4=2w. The next step to getting w by itself is to divide both sides by 2. So we end up with p/2 - 2=w.
anonymous
  • anonymous
Does this make sense?
anonymous
  • anonymous
yes know it does thank you
anonymous
  • anonymous
you're welcome!
anonymous
  • anonymous
could you help me in 2 more problems
anonymous
  • anonymous
yeah sure
anonymous
  • anonymous
ok a=s squared solve for s and the other ones is 3.14r squared solve for r
anonymous
  • anonymous
s = \[\sqrt{a}\] this is because \[\sqrt{s^{2}}\]=s, and what you do to one side you must do to the other.
anonymous
  • anonymous
and the other question is just \[3.14r^{2}\]? is it set equal to anything?
anonymous
  • anonymous
no it just says a=3.14r squared
anonymous
  • anonymous
ok, so first divide both sides by 3.14
anonymous
  • anonymous
then you're left with \[\frac{ a }{ 3.14 } = ^{2}\]
anonymous
  • anonymous
\[r^{2} *\]
anonymous
  • anonymous
so then we do the same thing as we did in the last problem...what you do to one side you must do to the other
anonymous
  • anonymous
so \[r = \sqrt{\frac{ a }{ 3.14 }}\]
anonymous
  • anonymous
ok thank you so munch you made it easier to me to understand I wish you were my teacher instead thank you so much
anonymous
  • anonymous
Aw well I'm glad I helped!! let me know if you have any other questions
anonymous
  • anonymous
oK THANK YOU :)

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