Can someone check my work please?
Its Rearranging Equations.

- karatechopper

Can someone check my work please?
Its Rearranging Equations.

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- karatechopper

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- karatechopper

##### 1 Attachment

- amistre64

try your #5 again

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## More answers

- karatechopper

Okay. Anything else?

- amistre64

dunno, i just got to the end of reading the sideways one ...

- karatechopper

ah ok

- karatechopper

Uhm...I got the same answer for #5. Could you walk me through after you are done checking?

- amistre64

pfft, they are both sides ways ... You seem to be dividing off a +2x in #5 ,,, when there is no multiplication to be undone

- amistre64

500 = 2x + y, solve for y

- amistre64

you did the same mistake in #7

- amistre64

and #8

- amistre64

and #10

- amistre64

youve made the same mistakes in those problems

- amistre64

for example:
14 = 6 + 8
14/6 = 8 is wrong ...

- amistre64

instead of dividing, what should we have done?

- karatechopper

OHHH!!!!!
SUBTRACTION FOR THE WIN!!!
Lemme get straight to work on that sir!

- amistre64

:)

- karatechopper

Makes sense as to why I was like,"Those answers are weird."

- karatechopper

So I think I got it..
#5= 500x-2x^2
#7= 108x^2-4x^3
#8=22x^3
#9= \[\frac{ 3w ^{2- w} }{ 2 }\]

- karatechopper

That w is not a part of the exponent btw..
and Thats 10. not 9 lol

- karatechopper

@amistre64 You there?

- amistre64

y = 500 -2x
A = x(500-2x) good
y = 108 - 4x
V = x^2(108-4x) good
4xy = 100-2x^2
2xy = 50- x^2
y = 25/x -x/2
V = x^2(25/x - x/2)
V = 25x - x^3/2 , rechk your #8

- amistre64

4wh = 3 - 2w^2
h = (3 - 2w^2)/w
V = w^2 (3-2w^2)/w
V = w (3-2w^2) rechk that one too #10

- amistre64

lost a 4 ...

- karatechopper

Can't 50/2x=25x?

- amistre64

x^2(50/2x) = 25x yes but thats only part of it

- karatechopper

Right. But in one or your steps for #8 you wrote 25/x. How did you get that? Could you walk me through number 8?

- amistre64

4xy = 100-2x^2 ; divide by 2, not needed but was something I did
2xy = 50- x^2 , divide by 2x and simplfy
/2x /2x /2x
--------------
y = 25/x -x/2
V = x^2(25/x - x/2)
V = 25x - x^3/2 , rechk your #8

- karatechopper

Seee!!!!
U wrote 50/2x and made it equal to 25/x. Thats different from 25x.

- amistre64

i plugged y into V

- amistre64

lets ignore the simplification ....
4xy = 100-2x^2 ; divide by 4x
y = (100-2x^2)/4x
V = x^2(100-2x^2)/4x
V = x(100-2x^2)/4

- amistre64

now when we simplify ...
x(100-2x^2)/4
(100x-2x^3)/4
100x/4 - 2x^3/4
25x - x^3/2

- karatechopper

I got lost..hm. Can I show you how I solved it?

- karatechopper

HOLD UP.
I GOT IT.

- karatechopper

Except for the fact.

- karatechopper

That I got a 25x^3

- karatechopper

not a reg 25x

- karatechopper

on number 10. Wouldn't that all be over 4?

- karatechopper

@KingGeorge Could you confirm for me on number 10?

- karatechopper

and 9.
Cuz I am just completely rooted and stuck

- KingGeorge

Let's start with 10. You start with \[3=2w^2+4wh,\]and want to solve for \(h\). The first thing you need to do is \(\bf subtract\) \(2w^2\) instead of dividing. So that will get you \[3-2w^2=4wh.\]Following me so far?
[If you divide you get \(3/(2w^2)=1+2h/w\)]

- KingGeorge

So long story short, #10 needs some fixing. But #9 looks correct to me.

- karatechopper

Wait. So. hold on start with 9. I is correct, what would be the answer then? Cuz I got like 3 different ones from resolving. Is it the one on the screenshot?

- karatechopper

and yes following you on number 10.

- KingGeorge

The one in the screenshot seems correct to me for 9.
The next step in 10, is to divide by \(4w\). This will get you\[\frac{3-2w^2}{4w}=\frac{3}{4w}-\frac{w}{2}\]

- karatechopper

ok.

- karatechopper

Understood that..

- KingGeorge

So that's your equation for \(h\). Plug that in, and you get\[V=w^2\left(\frac{3}{4w}-\frac{w}{2}\right)=\frac{3w}{4}-\frac {w^3}2\]

- karatechopper

I ended up with a w^3 at the end. not w^2

- karatechopper

Did u cross stuff out?

- KingGeorge

I have a w^3 at the end, and not a w^2....

- karatechopper

ohh ok! YESSSSS I GET IT!!!
Although then..did Amistre mess up on #9?

- KingGeorge

I don't think amistre ever mentioned 9.

- karatechopper

Oh i meant 8!!

- karatechopper

What do u think on that one?

- karatechopper

Cuz. I have seen different ways of solving :/

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