karatechopper
  • karatechopper
Can someone check my work please? Its Rearranging Equations.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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karatechopper
  • karatechopper
karatechopper
  • karatechopper
amistre64
  • amistre64
try your #5 again

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karatechopper
  • karatechopper
Okay. Anything else?
amistre64
  • amistre64
dunno, i just got to the end of reading the sideways one ...
karatechopper
  • karatechopper
ah ok
karatechopper
  • karatechopper
Uhm...I got the same answer for #5. Could you walk me through after you are done checking?
amistre64
  • amistre64
pfft, they are both sides ways ... You seem to be dividing off a +2x in #5 ,,, when there is no multiplication to be undone
amistre64
  • amistre64
500 = 2x + y, solve for y
amistre64
  • amistre64
you did the same mistake in #7
amistre64
  • amistre64
and #8
amistre64
  • amistre64
and #10
amistre64
  • amistre64
youve made the same mistakes in those problems
amistre64
  • amistre64
for example: 14 = 6 + 8 14/6 = 8 is wrong ...
amistre64
  • amistre64
instead of dividing, what should we have done?
karatechopper
  • karatechopper
OHHH!!!!! SUBTRACTION FOR THE WIN!!! Lemme get straight to work on that sir!
amistre64
  • amistre64
:)
karatechopper
  • karatechopper
Makes sense as to why I was like,"Those answers are weird."
karatechopper
  • karatechopper
So I think I got it.. #5= 500x-2x^2 #7= 108x^2-4x^3 #8=22x^3 #9= \[\frac{ 3w ^{2- w} }{ 2 }\]
karatechopper
  • karatechopper
That w is not a part of the exponent btw.. and Thats 10. not 9 lol
karatechopper
  • karatechopper
@amistre64 You there?
amistre64
  • amistre64
y = 500 -2x A = x(500-2x) good y = 108 - 4x V = x^2(108-4x) good 4xy = 100-2x^2 2xy = 50- x^2 y = 25/x -x/2 V = x^2(25/x - x/2) V = 25x - x^3/2 , rechk your #8
amistre64
  • amistre64
4wh = 3 - 2w^2 h = (3 - 2w^2)/w V = w^2 (3-2w^2)/w V = w (3-2w^2) rechk that one too #10
amistre64
  • amistre64
lost a 4 ...
karatechopper
  • karatechopper
Can't 50/2x=25x?
amistre64
  • amistre64
x^2(50/2x) = 25x yes but thats only part of it
karatechopper
  • karatechopper
Right. But in one or your steps for #8 you wrote 25/x. How did you get that? Could you walk me through number 8?
amistre64
  • amistre64
4xy = 100-2x^2 ; divide by 2, not needed but was something I did 2xy = 50- x^2 , divide by 2x and simplfy /2x /2x /2x -------------- y = 25/x -x/2 V = x^2(25/x - x/2) V = 25x - x^3/2 , rechk your #8
karatechopper
  • karatechopper
Seee!!!! U wrote 50/2x and made it equal to 25/x. Thats different from 25x.
amistre64
  • amistre64
i plugged y into V
amistre64
  • amistre64
lets ignore the simplification .... 4xy = 100-2x^2 ; divide by 4x y = (100-2x^2)/4x V = x^2(100-2x^2)/4x V = x(100-2x^2)/4
amistre64
  • amistre64
now when we simplify ... x(100-2x^2)/4 (100x-2x^3)/4 100x/4 - 2x^3/4 25x - x^3/2
karatechopper
  • karatechopper
I got lost..hm. Can I show you how I solved it?
karatechopper
  • karatechopper
HOLD UP. I GOT IT.
karatechopper
  • karatechopper
Except for the fact.
karatechopper
  • karatechopper
That I got a 25x^3
karatechopper
  • karatechopper
not a reg 25x
karatechopper
  • karatechopper
on number 10. Wouldn't that all be over 4?
karatechopper
  • karatechopper
@KingGeorge Could you confirm for me on number 10?
karatechopper
  • karatechopper
and 9. Cuz I am just completely rooted and stuck
KingGeorge
  • KingGeorge
Let's start with 10. You start with \[3=2w^2+4wh,\]and want to solve for \(h\). The first thing you need to do is \(\bf subtract\) \(2w^2\) instead of dividing. So that will get you \[3-2w^2=4wh.\]Following me so far? [If you divide you get \(3/(2w^2)=1+2h/w\)]
KingGeorge
  • KingGeorge
So long story short, #10 needs some fixing. But #9 looks correct to me.
karatechopper
  • karatechopper
Wait. So. hold on start with 9. I is correct, what would be the answer then? Cuz I got like 3 different ones from resolving. Is it the one on the screenshot?
karatechopper
  • karatechopper
and yes following you on number 10.
KingGeorge
  • KingGeorge
The one in the screenshot seems correct to me for 9. The next step in 10, is to divide by \(4w\). This will get you\[\frac{3-2w^2}{4w}=\frac{3}{4w}-\frac{w}{2}\]
karatechopper
  • karatechopper
ok.
karatechopper
  • karatechopper
Understood that..
KingGeorge
  • KingGeorge
So that's your equation for \(h\). Plug that in, and you get\[V=w^2\left(\frac{3}{4w}-\frac{w}{2}\right)=\frac{3w}{4}-\frac {w^3}2\]
karatechopper
  • karatechopper
I ended up with a w^3 at the end. not w^2
karatechopper
  • karatechopper
Did u cross stuff out?
KingGeorge
  • KingGeorge
I have a w^3 at the end, and not a w^2....
karatechopper
  • karatechopper
ohh ok! YESSSSS I GET IT!!! Although then..did Amistre mess up on #9?
KingGeorge
  • KingGeorge
I don't think amistre ever mentioned 9.
karatechopper
  • karatechopper
Oh i meant 8!!
karatechopper
  • karatechopper
What do u think on that one?
karatechopper
  • karatechopper
Cuz. I have seen different ways of solving :/

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