anonymous
  • anonymous
Find the average value for the length of an object with uncertainty if the 5 measurements are 87.5 cm, 88.0, 86.9 cm, 87.7cm and 88.0cm. Average value: Standard deviation: Standard error: Therefor, the average value with uncertainty is:___ how to do this? can i add them and divide them by 5? how about the second and 3rd question?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Luigi0210
  • Luigi0210
Oh, I used to be so good at this.. err
anonymous
  • anonymous
oh, so you can help me?? (^_^)
Luigi0210
  • Luigi0210
Oh how I wish I could data :/

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Luigi0210
  • Luigi0210
Does this have anything to do with linear approximation and differentials?
Luigi0210
  • Luigi0210
>.>
Loser66
  • Loser66
hehe, mistypo, I am sorry,
Loser66
  • Loser66
standard deviation is 87.45 standard error is 0.55 average value with uncertainty is 87.62
anonymous
  • anonymous
how did you get that?
Loser66
  • Loser66
standard deviation: (first + last)/2 standard error (last - first )/2 average (sum of 5 terms )/5
Loser66
  • Loser66
first means the least, last means the biggest number
anonymous
  • anonymous
ahhhhh....thank you very much:)

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