anonymous
  • anonymous
What is the equation of the line in standard form that passes through the point (–2, –3) and is parallel to the line y = x + 9?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Well, we know the equation for a line is \(y=mx+b\) Where \(m\) is its slope and \(b\) is the y-intercept. We also know that if Line A has a slope of \(m_1\) and Line B has a slope of \(m_2\), and Line A is parallel to Line B, then \(m_1=m_2\). So we can develop some things from here. One thing is that we know the mentioned line, has a formula of \(y=x+9\); from that, we can deduce that it has a slope of \(1\) and therefore, our line must also have a slope of \(1\) since they are parallel
anonymous
  • anonymous
So the formula for our line is: \[y=(1)x+b=x+b\] We can sub in a point we know: \[-3=-2+b\] And solve for \(b\) \[b=-3+2=-1\] So the formula would be \[y=x-1\]
anonymous
  • anonymous
A. x – y = 1 B. x + y = 1 C. x – y = –5 D. x + y = –5 are my answers to choose from

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anonymous
  • anonymous
First, find the slope of the equation of \[y = x + 9\] by using your slope-intercep form: \[y = mx + b\]. In this case, m = 1. Using the point slope formula \[(y-y1) = m(x-x1)\] Use this formula to plug in the numbers that have been provided. Points (-2,-3) and m = 1. Then solve for y.
anonymous
  • anonymous
Oh okay well, \[y=x-1\] \[y-x=-1\] \[-(y-x)=1\] \[x-y=1\] So the equation is A
anonymous
  • anonymous
Thank you bunches!! =)
anonymous
  • anonymous
Anytime :)

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