anonymous
  • anonymous
find the verticle asymptote of f(x)= 1/(x^2 -4) and describe the behavior of f(x) to the left and right of each asymptote? help PLEASE?D: (:
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
2 Vertical asymptotes. 1 at x=2, and the other at x=-2. Because (x^2-4) --> (x-2)(x+2)
anonymous
  • anonymous
or you could also say that they are going towards 0 because they never cross the x-axis
anonymous
  • anonymous

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anonymous
  • anonymous
is this the correct graph?
Hero
  • Hero
@SoccerGirl13, just out of curiousity, what kind of calculator do you have?
anonymous
  • anonymous
ti-84 :o
Hero
  • Hero
I see
Hero
  • Hero
Do you know how to program the function into your calculator?
Hero
  • Hero
If you did, that would help you out a lot
anonymous
  • anonymous
yes, but what i'm having trouble with is identifying the limits. :(
anonymous
  • anonymous
wait what do you mean by program the function into it?
Hero
  • Hero
If you don't know how to, then nevermind.
Hero
  • Hero
Explaining how to program a calculator from OS would be a project.
Hero
  • Hero
They question asked to explain the behavior of f(x) to the right and left of each asymptote.
anonymous
  • anonymous
yess, that was the second part of the question! :o
Hero
  • Hero
If you've already graphed the function, then I assume that you have already found the vertical asymptotes. And from the graph, you should be able to describe its behavior.
anonymous
  • anonymous
would you say that both sides are going towards zero, or that the left side is going towards negative infinity and right towards infinity? :o .__.
anonymous
  • anonymous
@Hero ? any clue? O; :(
Hero
  • Hero
In this case, one side is approaching infinity and the other is approaching y = 0

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