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When two equations are parallel, they have the same slopes.
So you have to first put -7x - 5y = 48 in slope intercept form, which is y=mx+b.
Alright. Could you possibly solve them and I'll work from the answer to see how it was done? I've spent the last two hours working and these are the last two questions I have.
So now you have the slope, -7/5, so plug this and the point (-9, -5) into the point slope formula: y-y1=m(x-x1)
Thank you! This helped quite a bit! I still am quite confused on the other question though.
I posted a picture earlier on in this post. It's number 49. I'm stuck on that one.
You just use rise/run. So pick a point on the graph. In this case, I can see (0,5). Then pick another point. I can also see (5,0).
Count how many times you move to the side and up to get from one point to the other. So to get from (5,0) to (0,5), you have to move to the left (run) 5 times and up (rise) 5 times.
Do you understand that, @Nawawi ?
I understand the concept I guess. But I'm not sure how to translate that to the form they want. The answers are like y=-x-6
Because you have to use the point-slope formula: y-y1=m(x-x1)
M is the slope and (x1,y1) is one of the points you choose from the graph.
I see what I did wrong. I'm so sorry. The points on the graph are (0,6) and (6,0). So your slope is -1 (because rise over run is 6/6 and the line is decreasing so it's negative 1). You plug into the formula I gave you using your slope and any point you want (Let's use 6,0): y-y1=m(x-x1) y-0=-1(x-6) Solve it out: y=-x+6
That's your answer. Sorry for my mistake.
Do you see what I did, @Nawawi ?
Yes! thank you for all the assistance! you have been a great help! I finally understand how to do these problems.