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love_jessika15
yes, so i know the volume of the drop and the radius of the oil drop when its laying in the water, so how do i find how thick the drop is as its laying in the water
\[V_{\text{sphere}} =\frac{4 \pi r^3}{3}\]
\[V_{\text{sphere}} = \frac{2(2r)r^2\pi}{3}\] 2r = height or thickness