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@jim_thompson5910 can you help?
if you have 2 points x and y on a number line, then the midpoint is (x+y)/2
So the midpoint is 7?
-2+12 is NOT 14
My bad it's 10 so the midpoint is 5?
So 5 is the answer, correct?
Can you help with 2 more questions?
solve for x (x+ 5)/2 = -1 then solve for y (y+2)/2 = 0
Im confused. how do i solve for x?
(x+ 5)/2 = -1 ... Start with the given equation x+5 = -1*2 ... Multiply both sides by 2. x+5 = -2 ... Multiply x = ???
x is 10?
2 times 5?
what undoes addition?
im so confused
-2 - 5 = ???
oh ok, -7?
so x = -7
ok and do the same thing for y?
Ok thanks so much! One more question?
are you familiar with the distance formula?
No i am not, sorry my connection keeps going out.
I recommend you reading this page http://www.purplemath.com/modules/distform.htm
to learn about the distance formula
Will the distance formula be needed for this problem?
yes it will
Ok one moment im gonna read that page.
Ok i see the distance formula.
Ok im gonna try and work this problem out, will you correct me if im wrong?
sure I can do that
im gonna work it out in worpad and copy and paste it here.
that sounds great
This is as far as i got d=sqrt(6-(-4))^2 + (1- (3))^2 = (6+4)^2 + (1+3)^2
good so far?
I forgot to put sqrt for the second part.
1-3 is not the same as 1+3
On the page you told me to look at the second part switched the addition.
the only reason why there was a sign change was because it wrote 1 - (-2)
that's the same as 1 + 2
ok, let me correct that in wordpad, one moment
Ok this is what i got. d=sqrt(6-(-4))^2 + (1- (3))^2 =sqrt (6-4)^2 + (1-3)^2 =sqrt(2)^2 + (-2)^2 =sqrt4+-4=sqrt8
right or wrong?
6-(-4) is the same as 6+4
1-(3) is just 1-3 = -2
Ok hold on.
d=sqrt(6-(-4))^2 + (1- (3))^2 =sqrt (6+4)^2 + (1-3)^2 =sqrt(10)^2 + (-2)^2 =sqrt100+-4=sqrt104 Is this now correct?
good, you can simplify that radical
How do i do that? I have to round to the nearest tenth, too?
oh no need to find the exact simplified answer just checked the instructions again and all they want is an approximate answer
so just type sqrt(104) into the calculator
ok, thats it? Even though it asks to round to the nearest tenth?
yes remember to round as well
what is sqrt(104) equal to?
My calculator doesn't have a sqrt button?
sqrt stands for "square root"
look for the square root symbol
I know, i'm using a ipod calculator, it doesn't have the sqrt symbol, i googled it though and it said this 10.1980390272
good, google works too
that rounds to what
10.2 is the answer of the whole problem, right?
yes it is
Ok thanks. i have one more questions. When constructing a an angle bisector, why must the arcs intersect?
is that all it asks?
or is there more to it?
The last one is the one i just posted about the angles. ^^^
for 100 + -4 im getting 96 now instead on 104?
it should be 100 + 4 = 104
not sure how you 100 + -4
so that 4 shouldn't be a negative? and i got it from (-2)^2 =-4
and i got that from 1-3^2
(-2)^2 is positive 4, not negative 4
Sorry, my mistake. Did you see the other question i posted?
Also i got that -4 from a calulator, it keeps saying (-2)^2 is -4
that's because you said -2^2 you should explicitly type in the parenthesis to say (-2)^2 = 4
Oh ok, i got it now. Did you see the other question?
Is it because of the vertex?
I think it's because the two arcs must intersect to form that new point that's needed to draw the angle bisector
Ok thanks for all the help! :)