Geometry question, picture attached, help?

- anonymous

Geometry question, picture attached, help?

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- anonymous

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- anonymous

@jim_thompson5910 can you help?

- jim_thompson5910

if you have 2 points x and y on a number line, then the midpoint is
(x+y)/2

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## More answers

- anonymous

So the midpoint is 7?

- jim_thompson5910

-2+12 is NOT 14

- anonymous

My bad it's 10 so the midpoint is 5?

- jim_thompson5910

good

- anonymous

So 5 is the answer, correct?

- jim_thompson5910

yes

- anonymous

Can you help with 2 more questions?

- jim_thompson5910

sure

- anonymous

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- jim_thompson5910

solve for x
(x+ 5)/2 = -1
then solve for y
(y+2)/2 = 0

- anonymous

Im confused. how do i solve for x?

- jim_thompson5910

(x+ 5)/2 = -1 ... Start with the given equation
x+5 = -1*2 ... Multiply both sides by 2.
x+5 = -2 ... Multiply
x = ???

- anonymous

x is 10?

- jim_thompson5910

no

- anonymous

2 times 5?

- jim_thompson5910

what undoes addition?

- anonymous

subtraction

- jim_thompson5910

yep

- anonymous

so 3?

- jim_thompson5910

no

- anonymous

im so confused

- jim_thompson5910

-2 - 5 = ???

- anonymous

oh ok, -7?

- jim_thompson5910

so x = -7

- anonymous

ok and do the same thing for y?

- jim_thompson5910

yes

- anonymous

y=-4?

- anonymous

Ok thanks so much! One more question?

- jim_thompson5910

ok

- anonymous

Last question.

##### 1 Attachment

- jim_thompson5910

are you familiar with the distance formula?

- anonymous

No i am not, sorry my connection keeps going out.

- jim_thompson5910

that's ok

- jim_thompson5910

I recommend you reading this page
http://www.purplemath.com/modules/distform.htm

- jim_thompson5910

to learn about the distance formula

- anonymous

Will the distance formula be needed for this problem?

- jim_thompson5910

yes it will

- anonymous

Ok one moment im gonna read that page.

- jim_thompson5910

alright

- anonymous

Ok i see the distance formula.

- jim_thompson5910

that's good

- anonymous

Ok im gonna try and work this problem out, will you correct me if im wrong?

- jim_thompson5910

sure I can do that

- anonymous

im gonna work it out in worpad and copy and paste it here.

- jim_thompson5910

that sounds great

- anonymous

This is as far as i got
d=sqrt(6-(-4))^2 + (1- (3))^2
= (6+4)^2 + (1+3)^2

- anonymous

good so far?

- anonymous

I forgot to put sqrt for the second part.

- jim_thompson5910

1-3 is not the same as 1+3

- anonymous

On the page you told me to look at the second part switched the addition.

- jim_thompson5910

the only reason why there was a sign change was because it wrote 1 - (-2)

- jim_thompson5910

that's the same as 1 + 2

- anonymous

ok, let me correct that in wordpad, one moment

- anonymous

Ok this is what i got.
d=sqrt(6-(-4))^2 + (1- (3))^2
=sqrt (6-4)^2 + (1-3)^2
=sqrt(2)^2 + (-2)^2
=sqrt4+-4=sqrt8

- anonymous

right or wrong?

- jim_thompson5910

that's incorrect

- jim_thompson5910

6-(-4) is the same as 6+4

- jim_thompson5910

1-(3) is just 1-3 = -2

- anonymous

Ok hold on.

- anonymous

d=sqrt(6-(-4))^2 + (1- (3))^2
=sqrt (6+4)^2 + (1-3)^2
=sqrt(10)^2 + (-2)^2
=sqrt100+-4=sqrt104
Is this now correct?

- jim_thompson5910

good, you can simplify that radical

- anonymous

How do i do that? I have to round to the nearest tenth, too?

- jim_thompson5910

oh no need to find the exact simplified answer
just checked the instructions again and all they want is an approximate answer

- jim_thompson5910

so just type sqrt(104) into the calculator

- anonymous

ok, thats it? Even though it asks to round to the nearest tenth?

- jim_thompson5910

yes remember to round as well

- jim_thompson5910

what is sqrt(104) equal to?

- anonymous

My calculator doesn't have a sqrt button?

- jim_thompson5910

sqrt stands for "square root"

- jim_thompson5910

look for the square root symbol

- anonymous

I know, i'm using a ipod calculator, it doesn't have the sqrt symbol, i googled it though and it said this 10.1980390272

- jim_thompson5910

good, google works too

- jim_thompson5910

that rounds to what

- anonymous

10.2?

- jim_thompson5910

very good

- anonymous

10.2 is the answer of the whole problem, right?

- jim_thompson5910

yes it is

- anonymous

Ok thanks. i have one more questions. When constructing a an angle bisector, why must the arcs intersect?

- jim_thompson5910

is that all it asks?

- jim_thompson5910

or is there more to it?

- anonymous

The last one is the one i just posted about the angles. ^^^

- anonymous

for 100 + -4 im getting 96 now instead on 104?

- jim_thompson5910

it should be 100 + 4 = 104

- jim_thompson5910

not sure how you 100 + -4

- anonymous

so that 4 shouldn't be a negative? and i got it from (-2)^2 =-4

- anonymous

and i got that from 1-3^2

- jim_thompson5910

(-2)^2 is positive 4, not negative 4

- anonymous

Sorry, my mistake. Did you see the other question i posted?

- anonymous

Also i got that -4 from a calulator, it keeps saying (-2)^2 is -4

- jim_thompson5910

that's because you said -2^2
you should explicitly type in the parenthesis to say (-2)^2 = 4

- anonymous

Oh ok, i got it now. Did you see the other question?

- anonymous

Is it because of the vertex?

- jim_thompson5910

I think it's because the two arcs must intersect to form that new point that's needed to draw the angle bisector

- anonymous

Ok thanks for all the help! :)

- jim_thompson5910

you're welcome

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