anonymous
  • anonymous
Geometry question, picture attached, help?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
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anonymous
  • anonymous
@jim_thompson5910 can you help?
jim_thompson5910
  • jim_thompson5910
if you have 2 points x and y on a number line, then the midpoint is (x+y)/2

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anonymous
  • anonymous
So the midpoint is 7?
jim_thompson5910
  • jim_thompson5910
-2+12 is NOT 14
anonymous
  • anonymous
My bad it's 10 so the midpoint is 5?
jim_thompson5910
  • jim_thompson5910
good
anonymous
  • anonymous
So 5 is the answer, correct?
jim_thompson5910
  • jim_thompson5910
yes
anonymous
  • anonymous
Can you help with 2 more questions?
jim_thompson5910
  • jim_thompson5910
sure
anonymous
  • anonymous
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jim_thompson5910
  • jim_thompson5910
solve for x (x+ 5)/2 = -1 then solve for y (y+2)/2 = 0
anonymous
  • anonymous
Im confused. how do i solve for x?
jim_thompson5910
  • jim_thompson5910
(x+ 5)/2 = -1 ... Start with the given equation x+5 = -1*2 ... Multiply both sides by 2. x+5 = -2 ... Multiply x = ???
anonymous
  • anonymous
x is 10?
jim_thompson5910
  • jim_thompson5910
no
anonymous
  • anonymous
2 times 5?
jim_thompson5910
  • jim_thompson5910
what undoes addition?
anonymous
  • anonymous
subtraction
jim_thompson5910
  • jim_thompson5910
yep
anonymous
  • anonymous
so 3?
jim_thompson5910
  • jim_thompson5910
no
anonymous
  • anonymous
im so confused
jim_thompson5910
  • jim_thompson5910
-2 - 5 = ???
anonymous
  • anonymous
oh ok, -7?
jim_thompson5910
  • jim_thompson5910
so x = -7
anonymous
  • anonymous
ok and do the same thing for y?
jim_thompson5910
  • jim_thompson5910
yes
anonymous
  • anonymous
y=-4?
anonymous
  • anonymous
Ok thanks so much! One more question?
jim_thompson5910
  • jim_thompson5910
ok
anonymous
  • anonymous
Last question.
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jim_thompson5910
  • jim_thompson5910
are you familiar with the distance formula?
anonymous
  • anonymous
No i am not, sorry my connection keeps going out.
jim_thompson5910
  • jim_thompson5910
that's ok
jim_thompson5910
  • jim_thompson5910
I recommend you reading this page http://www.purplemath.com/modules/distform.htm
jim_thompson5910
  • jim_thompson5910
to learn about the distance formula
anonymous
  • anonymous
Will the distance formula be needed for this problem?
jim_thompson5910
  • jim_thompson5910
yes it will
anonymous
  • anonymous
Ok one moment im gonna read that page.
jim_thompson5910
  • jim_thompson5910
alright
anonymous
  • anonymous
Ok i see the distance formula.
jim_thompson5910
  • jim_thompson5910
that's good
anonymous
  • anonymous
Ok im gonna try and work this problem out, will you correct me if im wrong?
jim_thompson5910
  • jim_thompson5910
sure I can do that
anonymous
  • anonymous
im gonna work it out in worpad and copy and paste it here.
jim_thompson5910
  • jim_thompson5910
that sounds great
anonymous
  • anonymous
This is as far as i got d=sqrt(6-(-4))^2 + (1- (3))^2 = (6+4)^2 + (1+3)^2
anonymous
  • anonymous
good so far?
anonymous
  • anonymous
I forgot to put sqrt for the second part.
jim_thompson5910
  • jim_thompson5910
1-3 is not the same as 1+3
anonymous
  • anonymous
On the page you told me to look at the second part switched the addition.
jim_thompson5910
  • jim_thompson5910
the only reason why there was a sign change was because it wrote 1 - (-2)
jim_thompson5910
  • jim_thompson5910
that's the same as 1 + 2
anonymous
  • anonymous
ok, let me correct that in wordpad, one moment
anonymous
  • anonymous
Ok this is what i got. d=sqrt(6-(-4))^2 + (1- (3))^2 =sqrt (6-4)^2 + (1-3)^2 =sqrt(2)^2 + (-2)^2 =sqrt4+-4=sqrt8
anonymous
  • anonymous
right or wrong?
jim_thompson5910
  • jim_thompson5910
that's incorrect
jim_thompson5910
  • jim_thompson5910
6-(-4) is the same as 6+4
jim_thompson5910
  • jim_thompson5910
1-(3) is just 1-3 = -2
anonymous
  • anonymous
Ok hold on.
anonymous
  • anonymous
d=sqrt(6-(-4))^2 + (1- (3))^2 =sqrt (6+4)^2 + (1-3)^2 =sqrt(10)^2 + (-2)^2 =sqrt100+-4=sqrt104 Is this now correct?
jim_thompson5910
  • jim_thompson5910
good, you can simplify that radical
anonymous
  • anonymous
How do i do that? I have to round to the nearest tenth, too?
jim_thompson5910
  • jim_thompson5910
oh no need to find the exact simplified answer just checked the instructions again and all they want is an approximate answer
jim_thompson5910
  • jim_thompson5910
so just type sqrt(104) into the calculator
anonymous
  • anonymous
ok, thats it? Even though it asks to round to the nearest tenth?
jim_thompson5910
  • jim_thompson5910
yes remember to round as well
jim_thompson5910
  • jim_thompson5910
what is sqrt(104) equal to?
anonymous
  • anonymous
My calculator doesn't have a sqrt button?
jim_thompson5910
  • jim_thompson5910
sqrt stands for "square root"
jim_thompson5910
  • jim_thompson5910
look for the square root symbol
anonymous
  • anonymous
I know, i'm using a ipod calculator, it doesn't have the sqrt symbol, i googled it though and it said this 10.1980390272
jim_thompson5910
  • jim_thompson5910
good, google works too
jim_thompson5910
  • jim_thompson5910
that rounds to what
anonymous
  • anonymous
10.2?
jim_thompson5910
  • jim_thompson5910
very good
anonymous
  • anonymous
10.2 is the answer of the whole problem, right?
jim_thompson5910
  • jim_thompson5910
yes it is
anonymous
  • anonymous
Ok thanks. i have one more questions. When constructing a an angle bisector, why must the arcs intersect?
jim_thompson5910
  • jim_thompson5910
is that all it asks?
jim_thompson5910
  • jim_thompson5910
or is there more to it?
anonymous
  • anonymous
The last one is the one i just posted about the angles. ^^^
anonymous
  • anonymous
for 100 + -4 im getting 96 now instead on 104?
jim_thompson5910
  • jim_thompson5910
it should be 100 + 4 = 104
jim_thompson5910
  • jim_thompson5910
not sure how you 100 + -4
anonymous
  • anonymous
so that 4 shouldn't be a negative? and i got it from (-2)^2 =-4
anonymous
  • anonymous
and i got that from 1-3^2
jim_thompson5910
  • jim_thompson5910
(-2)^2 is positive 4, not negative 4
anonymous
  • anonymous
Sorry, my mistake. Did you see the other question i posted?
anonymous
  • anonymous
Also i got that -4 from a calulator, it keeps saying (-2)^2 is -4
jim_thompson5910
  • jim_thompson5910
that's because you said -2^2 you should explicitly type in the parenthesis to say (-2)^2 = 4
anonymous
  • anonymous
Oh ok, i got it now. Did you see the other question?
anonymous
  • anonymous
Is it because of the vertex?
jim_thompson5910
  • jim_thompson5910
I think it's because the two arcs must intersect to form that new point that's needed to draw the angle bisector
anonymous
  • anonymous
Ok thanks for all the help! :)
jim_thompson5910
  • jim_thompson5910
you're welcome

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