anonymous
  • anonymous
49^(x+1)=square root of 7?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Ness9630
  • Ness9630
Get common bases, make both have a base of 7.
campbell_st
  • campbell_st
well rewrite each side of the equation in index form with the same base \[(7^2)^{(x + 1)} = 7^{\frac{1}{2}}\] which simplifies to \[7^{2x + 2} = 7 ^{\frac{1}{2}}\] now just equate the powers and solve for x
anonymous
  • anonymous
its \[\sqrt{7}\] not 7 \[\frac{ 1 }{ 2 } \]

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campbell_st
  • campbell_st
well well a little index information \[\sqrt{7} = 7^{\frac{1}{2}}\] to test it get a calculator and find \[\sqrt{7} =\] next, using the power key on your calculator find \[7^{\frac{1}{2}}.... or.... 7^{0.5}\] what happens...
anonymous
  • anonymous
oh!! okay so now ive got 2x+2 =\[\frac{ 1 }{ 2 }\] now what?
campbell_st
  • campbell_st
solve for x
AkashdeepDeb
  • AkashdeepDeb
@shaa Need help?
anonymous
  • anonymous
I got -1.25! that's wrong!
anonymous
  • anonymous
yes please explain!
AkashdeepDeb
  • AkashdeepDeb
Hold on for a sec... The answer should be.....
AkashdeepDeb
  • AkashdeepDeb
Is there an option such as -3/4?
anonymous
  • anonymous
Ive got no options
campbell_st
  • campbell_st
well the answer may need to be in fraction form to start so 2x + 2 = 1/2 subtract 2 2x = -3/2
AkashdeepDeb
  • AkashdeepDeb
-0.75 ?
AkashdeepDeb
  • AkashdeepDeb
Okay follow him. :D
anonymous
  • anonymous
so the answer is -1.75?
campbell_st
  • campbell_st
no... you have 2x = -3/2 divide both sides of the equation by 2 x = -3/4 to check if its correct, substitute into the original equation...
anonymous
  • anonymous
-0.75 I mean
anonymous
  • anonymous
sorry I typed it wrong haha! its -0.75 right?
campbell_st
  • campbell_st
well i'd probably write the answer is -3/4... but otherwise you're correct
anonymous
  • anonymous
finally! thanks so much for your help! :)
campbell_st
  • campbell_st
good luck with your maths

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