anonymous
  • anonymous
the sides of a triangle are in the ratio 5 12 13. what is the length of each side of the perimeter of the triangle is 90 cm? please answer :)))
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
campbell_st
  • campbell_st
add the parts of the ratio and divide the perimeter by your answer. This is called the unitary method... when you have the value of 1 unit multiply it by 5, 12 and 13 to get the side lengths.
anonymous
  • anonymous
The answer choices are A: 22.5, 30, 37.5cm, B: 19.3, 25.7, 32.1cm, C: 7.5, 11.5, 32.1cm, D: 10.5, 11.5, 12.5cm
campbell_st
  • campbell_st
I know the answers.... did you do the calculation...?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

campbell_st
  • campbell_st
and I don't think you have the correct answer choices to the question
anonymous
  • anonymous
yes I do pussy
campbell_st
  • campbell_st
ok... good luck with the answer.... because its not in the list of choices
anonymous
  • anonymous
7uck u pussy b!tch

Looking for something else?

Not the answer you are looking for? Search for more explanations.