anonymous
  • anonymous
Multiply: (x^(2) -4)/x^(2)) * (x^(2)-2x)/x^(2)+3x-10
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
\[\frac{ x ^{2} -4}{ x ^{2} } * \frac{ x^{2} - 2x }{ x^{2}+3x-10 }\]
anonymous
  • anonymous
So I factored it out to be \[\frac{ (x-2)(x+2) }{ x(x) }*\frac{ x(x-2) }{ (x+5)(x-2)}\]
anonymous
  • anonymous
And then I divided out to be \[\frac{ x+2 }{ x(x+5)}\] and that x cannot equal -5 and 2, but my homework is saying that's not correct. Can someone help me out? @phi @dan815

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phi
  • phi
you have (x-2) in the top twice. You can cancel one of them with the bottom (x-2), but that still leaves one up top
anonymous
  • anonymous
Alright, that's what I thought. is that all that I did wrong?
phi
  • phi
yes, all you need is multiply by (x-2) (up top)
anonymous
  • anonymous
So, my final product would look like {x+2 (x-2)/x(x+5)}
anonymous
  • anonymous
With x not being able to equal -5 or 2, and those two numbers only?
anonymous
  • anonymous
Okay so I got the question wrong because I did not include 0 as a number x cannot equal. Why would I need to include that if it is obvious and I did not need to include it on my other problems?
phi
  • phi
maybe because you canceled out an x. Technically you have a "double 0"
anonymous
  • anonymous
Can you explain that concept to me? I don't remember hearing it.
phi
  • phi
I think x/x^2 with x=0 is different from 1/x with x=0 but I am not a mathematician so I have no good explanation. Just a guess as to why they want x=0 listed in the excluded values.

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