anonymous
  • anonymous
I need help with graphs and functions..algebra 2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
anonymous
  • anonymous
And also, determine if y is a function to x. x^2 = 3y + y
anonymous
  • anonymous
@amistre64

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anonymous
  • anonymous
@ganeshie8
ganeshie8
  • ganeshie8
which q you stuck wid ? :)
anonymous
  • anonymous
29 and 30! And sorry is the picture up side down?
ganeshie8
  • ganeshie8
its okay :) look at the curve in pic 29, it is starting at 0, and going up forever.. so its range is : x >= 0
ganeshie8
  • ganeshie8
wat do you knw about its domain ?
anonymous
  • anonymous
it's infinite?
ganeshie8
  • ganeshie8
kindof yes :) for domain, you look left and right of curve, its goin forever in both directions. so domain is : all real numbers
ganeshie8
  • ganeshie8
basically we don this :- for range, look \(\text{up and down}\) of the curve for domain, look \(\text{look left and right}\) of the curve
ganeshie8
  • ganeshie8
can you do the same for pic 30, and tell me whats the range is ?
anonymous
  • anonymous
All I know is that 30 is not a function
ganeshie8
  • ganeshie8
thats right ! its not a function !!
ganeshie8
  • ganeshie8
for finding range, look up and down of that curve
anonymous
  • anonymous
so it doesnt have a domain or function?
anonymous
  • anonymous
or range* not function lol
ganeshie8
  • ganeshie8
down, it is -1, up it is +1 so the range is all numbers between -1 and 1 we represent it as : [-1, +1]
ganeshie8
  • ganeshie8
domain and range will be there for every relation
anonymous
  • anonymous
and is domain infinite again?
ganeshie8
  • ganeshie8
wat about domain for this ? :) look left and right, and see if u can figure this out...
ganeshie8
  • ganeshie8
noo.. look at the pic., this time, the curve is not going left and right forever
anonymous
  • anonymous
-3 and 3 ?
ganeshie8
  • ganeshie8
left, it stopped at -3 right, it stopped at +3 so the domain is all numbers between -3 and +3 we represent it as [-3, 3]
ganeshie8
  • ganeshie8
Excellent ! yes everything between -3 and 3
anonymous
  • anonymous
Ohh!:) thank you so much! and i need help with one more thing!
ganeshie8
  • ganeshie8
sure :)
anonymous
  • anonymous
determine if y is a function to x. x^2 = 3y + y
ganeshie8
  • ganeshie8
x^2 = 3y + y ? is the right side, really, 3y+y ?
anonymous
  • anonymous
yes
ganeshie8
  • ganeshie8
ok, solve y x^2 = 3y + y x^2 = 4y x^2.4 = y y = x^2/4
ganeshie8
  • ganeshie8
now graph this relation, and see vertical line test passes
ganeshie8
  • ganeshie8
|dw:1378416468569:dw|
ganeshie8
  • ganeshie8
when you graph it, it looks like above... does it look like a function ?
anonymous
  • anonymous
yess
anonymous
  • anonymous
thank you!! my math teacher sucks!!!
ganeshie8
  • ganeshie8
so yes ! y is a function of x in the given equation : x^2 = 3y + y
ganeshie8
  • ganeshie8
oh poor girl dont wry, its okay i can see you're very good in math :)
anonymous
  • anonymous
I kinda am it's just he is really weird at teaching
anonymous
  • anonymous
And he also has a weird habit of like touching his beard or like his chin and then smelling his fingers..super weird
ganeshie8
  • ganeshie8
lol thattttt weird really o.o
anonymous
  • anonymous
yeah! well thanks
ganeshie8
  • ganeshie8
np :)

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