I need help with graphs and functions..algebra 2

- anonymous

I need help with graphs and functions..algebra 2

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- anonymous

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- anonymous

And also, determine if y is a function to x.
x^2 = 3y + y

- anonymous

@amistre64

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## More answers

- anonymous

@ganeshie8

- ganeshie8

which q you stuck wid ? :)

- anonymous

29 and 30! And sorry is the picture up side down?

- ganeshie8

its okay :)
look at the curve in pic 29, it is starting at 0, and going up forever..
so its range is : x >= 0

- ganeshie8

wat do you knw about its domain ?

- anonymous

it's infinite?

- ganeshie8

kindof yes :)
for domain, you look left and right of curve, its goin forever in both directions.
so domain is : all real numbers

- ganeshie8

basically we don this :-
for range, look \(\text{up and down}\) of the curve
for domain, look \(\text{look left and right}\) of the curve

- ganeshie8

can you do the same for pic 30, and tell me whats the range is ?

- anonymous

All I know is that 30 is not a function

- ganeshie8

thats right ! its not a function !!

- ganeshie8

for finding range, look up and down of that curve

- anonymous

so it doesnt have a domain or function?

- anonymous

or range* not function lol

- ganeshie8

down, it is -1, up it is +1
so the range is all numbers between -1 and 1
we represent it as : [-1, +1]

- ganeshie8

domain and range will be there for every relation

- anonymous

and is domain infinite again?

- ganeshie8

wat about domain for this ? :)
look left and right, and see if u can figure this out...

- ganeshie8

noo.. look at the pic., this time, the curve is not going left and right forever

- anonymous

-3 and 3 ?

- ganeshie8

left, it stopped at -3
right, it stopped at +3
so the domain is all numbers between -3 and +3
we represent it as [-3, 3]

- ganeshie8

Excellent ! yes everything between -3 and 3

- anonymous

Ohh!:) thank you so much! and i need help with one more thing!

- ganeshie8

sure :)

- anonymous

determine if y is a function to x.
x^2 = 3y + y

- ganeshie8

x^2 = 3y + y
?
is the right side, really, 3y+y ?

- anonymous

yes

- ganeshie8

ok, solve y
x^2 = 3y + y
x^2 = 4y
x^2.4 = y
y = x^2/4

- ganeshie8

now graph this relation, and see vertical line test passes

- ganeshie8

|dw:1378416468569:dw|

- ganeshie8

when you graph it, it looks like above...
does it look like a function ?

- anonymous

yess

- anonymous

thank you!! my math teacher sucks!!!

- ganeshie8

so yes ! y is a function of x in the given equation :
x^2 = 3y + y

- ganeshie8

oh poor girl dont wry, its okay i can see you're very good in math :)

- anonymous

I kinda am it's just he is really weird at teaching

- anonymous

And he also has a weird habit of like touching his beard or like his chin and then smelling his fingers..super weird

- ganeshie8

lol thattttt weird really o.o

- anonymous

yeah! well thanks

- ganeshie8

np :)

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