anonymous
  • anonymous
3x^1/2-7x^1/4+1=0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[3x ^{1/2}-7x ^{1/4}+1=0\]
anonymous
  • anonymous
y = x^(1/4) so 3y^2 -7y+1=0 helps ?
anonymous
  • anonymous
Yes sir thanks, do you use the factoring formula?

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anonymous
  • anonymous
3y^2 -7y+1=0 you can solve it using quadratic formula
anonymous
  • anonymous
Thanks again, do I need to multiply it to the 4th power?
anonymous
  • anonymous
now when you found y you need to raise it to the 4th power as you said so you will get x.
anonymous
  • anonymous
7+√37/(6)^4, 7-√37/((6^4

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