anonymous
  • anonymous
Verify that the Intermediate Value Theorem applies to the indicated interval and find the value of "c" guaranteed by the theorem. f(x)=(x^2) + x - 1, [0,5] f(c) =11
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
do you just plug in 11?
anonymous
  • anonymous
well you first show that 11 is between f(0) and f(5) then in order to find c you solve: 11 = c^2 +c - 1
anonymous
  • anonymous
how do you show that 11 is between f(0) and f(5)?

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anonymous
  • anonymous
what is f(0) ?
anonymous
  • anonymous
do you just plug in 0 to the equation?
anonymous
  • anonymous
yes
anonymous
  • anonymous
f(0) = -1
anonymous
  • anonymous
good and f(5) ?
anonymous
  • anonymous
29
anonymous
  • anonymous
so 11 is really between them and according to the theorem there must be a value for c such that f(c) = 11
anonymous
  • anonymous
now find c 11=c^2 + c - 1
anonymous
  • anonymous
do I add over the 1 or subtract the 11?
anonymous
  • anonymous
@Coolsector
anonymous
  • anonymous
you better subtract the 11 so you will get quadratic equation
anonymous
  • anonymous
(x+4)(x-3)=0
anonymous
  • anonymous
but the answer in my book says f(3)=11, why not use f(-4) ?
anonymous
  • anonymous
because the interval was [0,5]
anonymous
  • anonymous
OH. wow okay LOL thank you
anonymous
  • anonymous
yw:)

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