anonymous
  • anonymous
Help with these 5 quick Pre-calculus questions?! Been stuck on these for ages!!!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
anonymous
  • anonymous
@Hero @UnkleRhaukus @RyanL. @dape ANYONE
dape
  • dape
For the first one, simply subtract g from f.

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dape
  • dape
In the second one \((g\circ f)(1)\) means \(g(f(1))\), so put 1 into f(x), you will get a number, put this number into g(x) and you get your answer.
dape
  • dape
#3, iterates means that you put the output of the function into the function again etc. You should start with \(x_0=0.1\), so calculate \(f(0.1)\), put this number into \(f(x)\), and that number into \(f(x)\) again etc. You will get a series of numbers which is the answer.
dape
  • dape
In #4 you should just add the functions. And in #5 you should put g(x) into f(x), which gives \((g\circ f)(x)\).
anonymous
  • anonymous
how would i do the first one? like i don't know how to subtract g from f.. @dape @Loser66 @skullpatrol
dape
  • dape
What is f(x) in #1?
anonymous
  • anonymous
9-x^2
dape
  • dape
Yes now subtract from that the expression for g(x).
anonymous
  • anonymous
so subtract 9-x^2 from 3-x?
dape
  • dape
The other way around, do \(9-x^2-(3-x)\)
dape
  • dape
Which is just \(f(x)-g(x).\)
anonymous
  • anonymous
how would i do that?
Loser66
  • Loser66
just subtract them as if you subtract 2 number, that's it.
dape
  • dape
Look at this video, it explains how you subtract polynomials. https://www.khanacademy.org/math/trigonometry/polynomial_and_rational/polynomial_tutorial/v/addition-and-subtraction-of-polynomials
anonymous
  • anonymous
so would it be 6-x?
Loser66
  • Loser66
9-x^2-3+x=?
anonymous
  • anonymous
how can i subtract x^2 from 9? and would the second part be 3x?
Loser66
  • Loser66
if you can't , neither I. let them there!!
dape
  • dape
You should carefully watch the video I posted, it's kind of important that you learn how to manipulate polynomials to do these kinds of problems.
anonymous
  • anonymous
@sam
anonymous
  • anonymous
@aaronq @Hero @inkyvoyd @Loser66 @nincompoop @wolf1728 CAN ANYONE JUST HELP WITH 4 AND 5?! I REALLY NEED JUST THE ANSWER. I'VE BEEN STUCK ON THEM FOR 2 HOURS.
anonymous
  • anonymous
which one?
anonymous
  • anonymous
ooh nvm 4 and 5
anonymous
  • anonymous
\[f(x)=2x^2+8,g(x)=5x-6\] \[f(x)+g(x)=2x^2+8+5x-6=2x^2+5x+2\] will work
anonymous
  • anonymous
So the answers would be 5x-6 and 2x^2+5x+2?
anonymous
  • anonymous
no, the answer is just \(2x^2+5x+2\)
anonymous
  • anonymous
for question number 4?
anonymous
  • anonymous
yes
anonymous
  • anonymous
okay, thanks! what about number 5?
anonymous
  • anonymous
\[f(x)\times g(x)=(x^2+8)(5x-6)\]
anonymous
  • anonymous
maybe you are supposed to multiply out
anonymous
  • anonymous
it looks like (f times g) (x)
anonymous
  • anonymous
yes exactly multiply \(f(x)\) times \(g(x)\)
anonymous
  • anonymous
how would i do that
anonymous
  • anonymous
\[f(x)\times g(x)=(x^2+8)(5x-6)=5x^3-6x^2+40x-48\]
anonymous
  • anonymous
so i would simplify 5x^3-6x^2+40x-48 to get my answer?
anonymous
  • anonymous
how?
anonymous
  • anonymous
you have no like terms to combine, so there is nothing you can do with this
anonymous
  • anonymous
so is that my answer?
anonymous
  • anonymous
yes
anonymous
  • anonymous
no!
anonymous
  • anonymous
ok so that is the answer to number 5?
anonymous
  • anonymous
aw
anonymous
  • anonymous
i made a mistake because i copied it wrong it is \[f(x)\times g(x)=(2x^2+8)(5x-6)\]
anonymous
  • anonymous
so what is the answer?
anonymous
  • anonymous
you should get \(10 x^3-12 x^2+40 x-48\)
anonymous
  • anonymous
so is that the answer?
anonymous
  • anonymous
yes
anonymous
  • anonymous
ok thank you!!! i may have a few more in a little
anonymous
  • anonymous
yw
anonymous
  • anonymous
can i have help with this last one and then i'm done. @satellite73
anonymous
  • anonymous
@satellite73 @Hero
anonymous
  • anonymous
\[g\circ f(4)=g(f(4))\] so the first step is to find \(f(4)\) let me know what you get
anonymous
  • anonymous
the hint is a little weird, because the top says \(g\circ f(4)\) but then hint has \(g\circ f(-4)\)
anonymous
  • anonymous
i don't know how to do that though..
anonymous
  • anonymous
do you know how to find \(f(4)\) if \(f(x)=x^2+3\) ?
anonymous
  • anonymous
no
anonymous
  • anonymous
then you need to learn how to do it where you see an \(x\) in \(x^2+3\) replace it by \(4\)
anonymous
  • anonymous
so it would be 4^2+3? which would be 19
anonymous
  • anonymous
yes
anonymous
  • anonymous
then since \[f(4)=19\] you know \[g(f(4))=g(19)\] now since \[g(x)=\frac{x+5}{x}\] your job is to find \(g(19)\)
anonymous
  • anonymous
i.e. where you see \(x\) in \(\frac{x+5}{x}\) replace it by \(19\)
anonymous
  • anonymous
so it would be g(x) 19+5 over 19?
anonymous
  • anonymous
equals*
anonymous
  • anonymous
and that would be g(x) = 24/19 which is one of my answers. is that correct?
anonymous
  • anonymous
@satellite73
anonymous
  • anonymous
nevermind, it was right. i got it

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