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ah you want to find the value of c? first, lets simplify this equation together! That is what you are asking, isn't it...
Yes Thanks!!!! Finally I get it Okay she said we need to simplify then use inverse then prove it and then do our properties
right, you simplify by distributing, add the like terms together, then you solve for c just like in a regular equation! :)
okay so I don't think there is anything we can simplify
Ok I guess that's correct thank you...... :)
- 27=3c-3(6-2c) First, distribute -3 to the parenthesis so -27 = 3c-18+6c add like terms -27 = 9c - 18 To get c, transpose -18 to the other side -27 + 18 = 9c -9 = 9c divide both sides by 9 so c=-1
wait that's not right but thank you I messed up and put -27 and it is just 27
thanks for explaining @petiteme , but I was hoping to get @haburke to figure it out by him/her self lol well that's okay, glad you get it now :)
No it wasn't right Jaimerox4ev3r I messed up and put - 27
Sorry :) @haburke if its not -27, just follow the steps :)
ok thanks to you both
and plug the variable back into the equation, that should help you a lot! :) This will also help prove whether you are correct or not
okay now I have another one but I got the answer and it works in the calculator but not when I try to prove it
3+4(z+5)=3 I got z= 2
distribute first 4 to the (z + 5)
substitute z by 2 :)
lets double check by plugging in the values. 3+4(2+5)=3 3+8+20 does not equal 3....so that means taht 2 is not a correct answer. Let me walk you through a process similar to the one @petiteme showed earlier
So first, use distribution 3+4(z+5)=3 3+4z+20=3 Then add like terms 23+4z=3 Subtact 23 from both sides 23+4z=3 -23 -23 --------- 4z=-20 divide by 4 4z=-20 /4 /4 z=-5 ^ and that right there should be your answer :)
ok see i did this : 3=4(z+15)=3 3+4z+20=31 4z+23=31 4z+23-23=31-23 4z=8 4z/4=8/4 z=2
how did you get 31 is my question? also, why do you have 15 in your top line inside the parentheses, i thought it was 5!. All of what you did seems correct, just not sure how you got 31.
Okay the original problem was 3+4(z+5)=40
crud no 31
the original problem is 3+4(z+5)=31
wait so you wrote the problem wrong? O.o if so, rewrite it correctly please lol and then I can try to double check and solve it again :P if need be
Okay I just cant type well today : 3+4(z+15)=31 3+4z+20=31 4Z+23=31 -23 -23 4Z= 8 4Z/4=8/4 Z=2
is it really 15 or 5?
its 15 i just messed up sorry
its okay :) if its 15, check your calculations. while distributing 4, 4(15) is not 20 :)