anonymous
  • anonymous
plzz help me ASAP..!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1378426931994:dw|
dape
  • dape
Start by factoring each of the numbers under the root-sign.
anonymous
  • anonymous
cn u shw hw??

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anonymous
  • anonymous
@dape ???
petiteme
  • petiteme
start by factoring first 45, 50, 147 under their root
anonymous
  • anonymous
am learnin dis fo first tym..cn u shw hw..??@petiteme
petiteme
  • petiteme
what are the factors of 45?
anonymous
  • anonymous
uhm..5,9,1,45
petiteme
  • petiteme
so 9*5 right? then its like this \[8\sqrt{9*5}\]
petiteme
  • petiteme
do it also to \[2\sqrt{50} - 3\sqrt{147}\]
petiteme
  • petiteme
nope. find the factors wherein you can use the square root. so this is the right one \[2\sqrt{25*2}\]
petiteme
  • petiteme
its \[3\sqrt{49*3}\]
petiteme
  • petiteme
So we got \[8\sqrt{9*5} + 2\sqrt{2*25} - 3\sqrt{49*3}\]
anonymous
  • anonymous
ohk..den
petiteme
  • petiteme
perform the square root :) First, \[2\sqrt{9*5}\]\[8*3 \sqrt{5}\] because the square root of 9 is 3. We put 3 already outside the square root :)
petiteme
  • petiteme
Second, \[2\sqrt{2*25} \] the square root of 25 is 5 so \[2*5 \sqrt{2}\] we put the 5 outside the square root
petiteme
  • petiteme
Third, \[3\sqrt{49*3}\] the square root of 49 is 7 so \[3*7\sqrt{3}\] we put 7 outside the square root
petiteme
  • petiteme
So its \[8*3\sqrt{5} +2*5\sqrt{2} - 3*7\sqrt{3}\] Do the math \[24\sqrt{5} + 10\sqrt{2} - 21\sqrt{3}\]
petiteme
  • petiteme
@juhaINA do you get it? :)
anonymous
  • anonymous
yup
anonymous
  • anonymous
thnx soo muJ
petiteme
  • petiteme
you're welcome :) anytime :)

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