anonymous
  • anonymous
for the love of god ive been up all night someone please just tell me the answers to each of these -2<2x-4<4 2|3x-5|-8=8 6|6-4x|=8x +4 8|x+ 30ver4|<2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
the last one is supposed to say 3 over 4
anonymous
  • anonymous
\[6\left| 6-4x \right|=8x+4\] \[\left| 6-4x \right|=\frac{ 8x+4 }{ 6 }\] \[6-4x=\pm \frac{ 8x+4 }{ 6 }\]
anonymous
  • anonymous
whats the answer haha

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More answers

anonymous
  • anonymous
\[either 6-4x=\frac{ 8x+4 }{6 }\] 6(6-4x)=8x+4 36-24x=8x+4 36-4=8x+24x 32x=32,x=32/32=1
anonymous
  • anonymous
ok that was correct what are the other answers
anonymous
  • anonymous
\[or6-4x=-\frac{ 8x+4 }{6 }\] 6(6-4x)=-(8x+4) 36-24x+8x+4=0 36+4=24x-8x 16x=40 x=40/16=5/2
anonymous
  • anonymous
answer my other questions not just that one
anonymous
  • anonymous
i solved a bit difficult ,others ar easy. you start i will guide you.
anonymous
  • anonymous
omg
anonymous
  • anonymous
let us start with first. write the statement first.
anonymous
  • anonymous
then add 4 in all the three inequalities.
anonymous
  • anonymous
6?
anonymous
  • anonymous
not like this -2+4<2x-4+4<4+4 2<2x<8 now divide each inequality by 2
anonymous
  • anonymous
1
anonymous
  • anonymous
how you got 6 ?
anonymous
  • anonymous
now write the second statement and show me.
anonymous
  • anonymous
\[2\left| 3x-5 \right|-8=8\] \[2\left| 3x-5 \right|=8+8\] \[\left| 3x-5 \right|=\frac{ 16 }{2 }=8\] \[3x-5=\pm8\]
anonymous
  • anonymous
either 3x-5=8 or 3x-5=-8 now you can solve these equations for x.
anonymous
  • anonymous
are you solving ?
anonymous
  • anonymous
\[8\left| x+\frac{ 3 }{4 } \right|<2\] \[\left| x+\frac{ 3 }{4 } \right|<\frac{ 2 }{8}\] \[\left| x+\frac{ 3 }{ 4 } \right|<\frac{ 1 }{4 }\] \[-\frac{ 1 }{ 4 }

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