anonymous
  • anonymous
I need help, I still have to study for other tests and it's already 11'o clock
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
decide whether the part of the waveform that is below the x - axis is a glide reflection of the part that is above. if it is, write the translation using a vector in component form https://watertowngeometry.wikispaces.com/file/view/7_5+Assignment.pdf go to the top of page 5 thos are the four problems i'm doing
anonymous
  • anonymous
those*
jim_thompson5910
  • jim_thompson5910
if you look at #14, you'll see that you can shift the top part above the x axis til the top squares line up with the bottom squares then you can reflect those top squares over the x axis to get them to match up with the bottom squares so this shows you that #14 has a glide reflection

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anonymous
  • anonymous
ok so we know for sure that this is one but what about the rest are those all no glide reflections?
jim_thompson5910
  • jim_thompson5910
which of the others are glide reflections? which of the others are not glide reflections?
anonymous
  • anonymous
i think number 12 is it is equal on both sides of the x - axis and think 15 is to but 13 isn't
jim_thompson5910
  • jim_thompson5910
12 and 15 are glide reflections 13 is not all are correct
anonymous
  • anonymous
awesome alright my next problem is that it says that if it is i need to write a translation using a vector in component for. i looked up what a vector means but what is it and what is it in component form?
jim_thompson5910
  • jim_thompson5910
component form is (x,y) or
jim_thompson5910
  • jim_thompson5910
ex: <2,3> means you shift to the right 2, and up 3
anonymous
  • anonymous
so then #12 is to the right 4 and down 4 and reflect right?
jim_thompson5910
  • jim_thompson5910
no
jim_thompson5910
  • jim_thompson5910
you need to shift the top then reflect over the x axis to get it to match up with the bottom
anonymous
  • anonymous
ok then 4 to the right and reflect?
jim_thompson5910
  • jim_thompson5910
how are you getting 4?
anonymous
  • anonymous
well then what would it be like 0.7~9
jim_thompson5910
  • jim_thompson5910
I count 2 spaces over (or 2 units) so whatever that converts to on the x scale given is the translation you want
jim_thompson5910
  • jim_thompson5910
see how I'm getting 2 ?
anonymous
  • anonymous
no
jim_thompson5910
  • jim_thompson5910
focus on the top squares above the x axis in #14
jim_thompson5910
  • jim_thompson5910
if you slide them over 2 spots to get them to line up above the bottom squares
anonymous
  • anonymous
oh lol i was talking about #12 sorry
anonymous
  • anonymous
so it would be (2,0)? right
jim_thompson5910
  • jim_thompson5910
well you have to change that 2 to whatever 2 units corresponds to
jim_thompson5910
  • jim_thompson5910
notice how the x scale starts at x = 0 and goes to x = 0.1
jim_thompson5910
  • jim_thompson5910
so 2 units doesn't correspond to 2 if the x scale had each tick mark at a whole number, then it would work
anonymous
  • anonymous
right i have to figure that out so 0.05
jim_thompson5910
  • jim_thompson5910
what's the distance from 0 to 0.1
anonymous
  • anonymous
10 units
jim_thompson5910
  • jim_thompson5910
no
anonymous
  • anonymous
you're not counting the edges them being rounded makes it more confusing
jim_thompson5910
  • jim_thompson5910
what do you mean?
anonymous
  • anonymous
the edges are rounded on the graph and i think how the numbers are placed you are counting them before the tick marks they are supposedly set at
jim_thompson5910
  • jim_thompson5910
yeah you don't count the starting tick mark, but the answer isn't 10
anonymous
  • anonymous
i thought that 0.0 is the origin in this case right?
jim_thompson5910
  • jim_thompson5910
0.0 isn't the same as (0,0)
jim_thompson5910
  • jim_thompson5910
the 0.0 you're looking at refers to x = 0.0 or x = 0
anonymous
  • anonymous
i thought it was cause on any graph it is the start right?
jim_thompson5910
  • jim_thompson5910
yes they all start at x = 0
anonymous
  • anonymous
and this one ends on 0.10 or 0.1
jim_thompson5910
  • jim_thompson5910
yes that's what you need to watch out for
anonymous
  • anonymous
so then the vector or whatever would be (0.05,0)
jim_thompson5910
  • jim_thompson5910
close, but no
anonymous
  • anonymous
then would it be (0.045,0)
jim_thompson5910
  • jim_thompson5910
each tick mark represents 0.1/8 = ???
anonymous
  • anonymous
0.0125?
anonymous
  • anonymous
right?
jim_thompson5910
  • jim_thompson5910
good, so 2 of those tick marks represent how many units?
anonymous
  • anonymous
0.025
jim_thompson5910
  • jim_thompson5910
yep
jim_thompson5910
  • jim_thompson5910
so the translation vector is <0.025, 0> then you reflect over the x axis
anonymous
  • anonymous
oh ok
anonymous
  • anonymous
so then 15 would be (0.025,0) then reflect across the x
anonymous
  • anonymous
and 12 would be (0.05,0) reflect across the x
anonymous
  • anonymous
am i right?
jim_thompson5910
  • jim_thompson5910
both are correct
anonymous
  • anonymous
OMG FINALLY I have had this question posted since 6 eastern time and finally it's answered
jim_thompson5910
  • jim_thompson5910
glad to be of help
anonymous
  • anonymous
well hopefully i will have you help in future posts thanks
Candy13106
  • Candy13106
so did u ever get wat u need to
anonymous
  • anonymous
yeah
Candy13106
  • Candy13106
oh than close it
Candy13106
  • Candy13106
u herd me didnt u
anonymous
  • anonymous
jezz calm down dude i will
Candy13106
  • Candy13106
ok well im not jezz now lay off by the way im am girl
anonymous
  • anonymous
i call everyone dude
Candy13106
  • Candy13106
oh ok i see do u need help on any other questions
Candy13106
  • Candy13106
ill help
Candy13106
  • Candy13106
wat grade r u in
anonymous
  • anonymous
nope i just have to study for a spanish test and finish reading a summer reading book but thank you, i'm in 10th grade
Candy13106
  • Candy13106
ok kool me 7 th but me a straight a student can u help me on my questions
anonymous
  • anonymous
sure
Candy13106
  • Candy13106
ok well it has to be some where at the bottom
anonymous
  • anonymous
k
Candy13106
  • Candy13106
kk

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