anonymous
  • anonymous
Express with positive exponents. (a^-1b^2)^-2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
a negative exponent is just like a division so n^-2 = 1/n^2
anonymous
  • anonymous
So how would do I apply to 2 variables? D:
anonymous
  • anonymous
first use that rule on the outer most exponent and leave the inside studd alone. what do you get

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anonymous
  • anonymous
stuff*
anonymous
  • anonymous
1/a^-1b^2 ?
anonymous
  • anonymous
its actually 1/(a^-1*b^2)^2 i think you just forgot the 2 on the bottom
anonymous
  • anonymous
now takle the inside of the expression
anonymous
  • anonymous
Would there be a negative sign before 1/(a^-1b^2)^2 ?
anonymous
  • anonymous
no. that negative in the exponent goes away when its shifted under a division like that
anonymous
  • anonymous
Ohhh, so for example if it was 2^-3 it would become 1/2^3 without the negative?
anonymous
  • anonymous
you got it :)
anonymous
  • anonymous
So would the final answer be 1/(a^1b^4) ?
anonymous
  • anonymous
well from where we left off at 1/(a^-1*b^2)^2 becomes 1/((1/a)*b^2)^2 the a^-1 turned to 1/a
anonymous
  • anonymous
Shoot right, I forgot the negative for a.... so after this would there be another step to finally solve b as well?
anonymous
  • anonymous
well technically you could leave it like it is since all exponents are positive
anonymous
  • anonymous
Alright, THANK YOU SO MUCH! :)
anonymous
  • anonymous
no problem. glad to help :)

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