anonymous
  • anonymous
Please help. Photo attached!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
ASAP please
anonymous
  • anonymous
If you take any pair point in table 3 you'll see that for every 2 units in x, y is increasing by 5 units The linear function is defined by (y-y1) = m(x-x1) where (x1, y1) match with any random pair in table and m is the slope defined by:\[m=\frac{ y2-y1 }{ x2-x1 }\] where (x1, y1) is any point at the left and (x2, y2) is any point at the right
anonymous
  • anonymous
ok so Table 3 is Linear... what is the equation of the linear function represented by that table? @ruizgeorge

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anonymous
  • anonymous
solving m for two random point in table Let's take (x1, y1) = (2,1) and (x2, y2) = (4,6) \[m = \frac{ 6-1 }{ 4-2 } = \frac{ 5 }{ 2 }\] Now take (x1, y1) to the equation with m \[y-1 = \frac{ 5 }{ 2 } (x-2)\] Solve for y !
anonymous
  • anonymous
6- 1 = 5/2 (4-2) @ruizgeorge am i right?
anonymous
  • anonymous
Nope Just let y as y and x as x
anonymous
  • anonymous
..... my so is the 4 actually 6? and 6 actully 4?
anonymous
  • anonymous
4-1 = 5/2 (6-2) ?
anonymous
  • anonymous
\[y = \frac{ 5 }{ 2 } x - \frac{ 5 }{ 2 } (2) + 1\] solve and simplify
anonymous
  • anonymous
i really dont know.
anonymous
  • anonymous
it's done \[y-y1 = m(x-x1)\] leads to the equation \[y-1=\frac{ 5 }{ 2 } (x-2)\] and solving for y: \[y = \frac{ 5 }{ 2 }x - 4\] (This is the linear equation for data in table #3) and that's all!
anonymous
  • anonymous
Oh wow.... thanks!

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