anonymous
  • anonymous
Solid Mensuration :)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
hey harttn you can view the prob I attached just now :D
hartnn
  • hartnn
i was viewing that only join FC then, can you find EF ?

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hartnn
  • hartnn
because you will know FC and EC
anonymous
  • anonymous
ok i''ll work on it, wait a minute :)
hartnn
  • hartnn
sure, take your time... ask me if you want to know how to get EF
anonymous
  • anonymous
ok, nah. i know how to ;) thx
anonymous
  • anonymous
using Pythagorean Theorem EF=\[6\sqrt{6}\], am I right?
hartnn
  • hartnn
good :)
hartnn
  • hartnn
now, what you know about FG and DG
anonymous
  • anonymous
yes! what would be the next step?
hartnn
  • hartnn
like you know why FG and DG are equal ? let them be 'x'
anonymous
  • anonymous
i know why're they're equal :) because they're both tangent lines intersecting at one point, right? :D
hartnn
  • hartnn
good :) so, now see right triangle EGD GD = x hypo = EF+x ED .....you know
anonymous
  • anonymous
OH! we'll be able to get DG! hahaha it will be like this: \[(6\sqrt{6}+x)^{2}=18^{2}+x ^{2}\] solving for x.....x=3.67in :D right?
hartnn
  • hartnn
i didn't check, i am helping 4 ppl at a time :P give me some time to verify....
anonymous
  • anonymous
ok ok haha :) its ok take your time!
hartnn
  • hartnn
yes, i get 3.674 too
anonymous
  • anonymous
now we got DG, we need to get the area enclosed by FG and DG, and arc FD
hartnn
  • hartnn
hint : area of rhombus FCDG - area of sector
hartnn
  • hartnn
***sector FCD
hartnn
  • hartnn
makes sense ? or should i elaborate ?
anonymous
  • anonymous
no! its ok :) no need to ^^

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