anonymous
  • anonymous
if a+b=3 and a^2+b^2=7, then what is the value of a^4 +b^4?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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hartnn
  • hartnn
can you find ab first ? from a+b and a^2+b^2 ?
hartnn
  • hartnn
because, you'll need a^2b^2
anonymous
  • anonymous
1+2=3?

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anonymous
  • anonymous
For the first part
hartnn
  • hartnn
1+2 ? you guessing nu,bers ?
anonymous
  • anonymous
Yes
hartnn
  • hartnn
use this : \((a+b)^2 = a^2+b^2+2ab\) to find the value of ab can u?
anonymous
  • anonymous
no quite
hartnn
  • hartnn
you know values of a+b and a^2+b^2 just plug those in that formula...
hartnn
  • hartnn
\((a+b)^2 = a^2+b^2+2ab\) (3)^2 = 7+2ab
hartnn
  • hartnn
now ?
anonymous
  • anonymous
Yes, thanks
anonymous
  • anonymous
3/2=ab
hartnn
  • hartnn
good, so once you have ab, use this (a^2+ b^2) ^2 = (a^4+ b^4) + 2 a^2b^2 you know a^2+b^2 , a^2b^2 , and you need a^4+b^4
hartnn
  • hartnn
and ab is NOT 3/2 try again ?
anonymous
  • anonymous
ab=1?
hartnn
  • hartnn
yup, ab =1 is correct :)
anonymous
  • anonymous
-1=a^4+b^4
hartnn
  • hartnn
lets check (a^2+ b^2) ^2 = (a^4+ b^4) + 2 a^2b^2 7^2 = (....) + 2 (1) how you got -1 ? :O
anonymous
  • anonymous
I got confused (a^2... with a+b
anonymous
  • anonymous
47=a^4+b^4
hartnn
  • hartnn
i get 47 too :)
anonymous
  • anonymous
Thanks so much! You are awesome:)
hartnn
  • hartnn
your welcome ^_^ you are a good learner too.

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