The diameter of the Earth is 7926 miles at its equator. The highest point on Earth (Mt. Everest) is 5.5 miles above sea level; the lowest point (Mariana Trench in the Pacific Ocean) is 6.8 miles below sea level. Hence, the "roughness" of the Earth’s surface is 5.5+6.8 = 12.3 miles. What is the ratio of the roughness of the Earth's surface to the Earth’s diameter? Express this ratio to a precision of one decimal place both in scientific notation and as a percentage.
I think I've got the ratio and the percentage correct,I'm not really sure what he's asking me to put in scientific notation?
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Precision should be to ONE DECIMAL PLACE...
He is asking you to round it off to one decimal place...
What is the ration, Tell me what you got. :D
The ratio starts as 12.3:7926. Complete the division and you get 1:644.4. This is equal to 0.2%
So 0.2% means 0.2/100 or 0.002
So in scientific notation anything is written in the form
a * 10^z [Where z is the power of 10]
a is a number between 1 and 10.
So 0.2% is written in scientific notation as
2 * 10^-4