The diameter of the Earth is 7926 miles at its equator. The highest point on Earth (Mt. Everest) is 5.5 miles above sea level; the lowest point (Mariana Trench in the Pacific Ocean) is 6.8 miles below sea level. Hence, the "roughness" of the Earth’s surface is 5.5+6.8 = 12.3 miles. What is the ratio of the roughness of the Earth's surface to the Earth’s diameter? Express this ratio to a precision of one decimal place both in scientific notation and as a percentage.
I think I've got the ratio and the percentage correct,I'm not really sure what he's asking me to put in scientific notation?

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The ratio starts as 12.3:7926. Complete the division and you get 1:644.4. This is equal to 0.2%

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