anonymous
  • anonymous
Write the equation of the quadratic function with roots -9 and and -3 and a vertex at (-6, -1). Answer
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
please help
anonymous
  • anonymous
you can always write parabola as \[y=a \left( x-x _{1} \right)\left( x-x _{2} \right)\] where x1 and x2 are roots of parabola and a is just constant
anonymous
  • anonymous
so it would be y=a(x+9)(x+3)

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anonymous
  • anonymous
yes thats right and now substitute vortex point in the ecuation and you will get a
anonymous
  • anonymous
-6(x+9)(x+3) like tht?
anonymous
  • anonymous
did you substitute -6 for x and -1 for y? because i got different a
anonymous
  • anonymous
idk how to do this
anonymous
  • anonymous
i got f(x)=x^2-12x+27
anonymous
  • anonymous
a(-6+9)(-6+3)=-1
anonymous
  • anonymous
a(3*-3)=-1 a(-9)=-1
anonymous
  • anonymous
a=8
anonymous
  • anonymous
?
anonymous
  • anonymous
why are you adding 9 when you should divide by 9
anonymous
  • anonymous
so its 1/9
anonymous
  • anonymous
yes
anonymous
  • anonymous
thanks now wat do i do if i want the full equation
anonymous
  • anonymous
multiply out (1/9)(x+9)(x+6)
anonymous
  • anonymous
ok just a moment
anonymous
  • anonymous
not x+6 a should write x+3
anonymous
  • anonymous
sorry :)
anonymous
  • anonymous
ok i got
anonymous
  • anonymous
x^2/9+4x+3+3
anonymous
  • anonymous
i wrote wrong equation up (1/9)(x+3)(x+9) :D sorry about that
anonymous
  • anonymous
ok
anonymous
  • anonymous
im so confused can you tell me the equation you got
anonymous
  • anonymous
what confusis you? y=a(x-x1)(x-x2) you know a x1 and x2 put them in you will get y=(1/9)(x+3)(x+9) now multiply it out and you will get answer
anonymous
  • anonymous
y=1/9x^2-1.3x+3
anonymous
  • anonymous
4/3 is not 1.3
anonymous
  • anonymous
i think you have some problems in arithamtics
anonymous
  • anonymous
ok first just multipla (x+9)(x+3)=x^2+3x+9x+27=x^2+12x+3
anonymous
  • anonymous
This is wrong because i put this in a calculator that determines the equations for quadratic functions and it said that this equation is with the toots of 9,3 and the vertex is -6,1
anonymous
  • anonymous
which equation y=(1/9)(x+9)(x+3) is wright
anonymous
  • anonymous
you just multiplied it out wrongly
anonymous
  • anonymous
you must get x^2/9+4x/3+3
anonymous
  • anonymous
oh thank u so much got the answer i appreciate your patience
anonymous
  • anonymous
it was my foult i'm not great at explaning :)

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