anonymous
  • anonymous
What mass of oxygen is needed for the complete combustion of 4.60×10−3g of methane?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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UnkleRhaukus
  • UnkleRhaukus
first you should start with a chenmical equation for the combustion
UnkleRhaukus
  • UnkleRhaukus
do you know the chemical formula of oxygen and methane?
anonymous
  • anonymous
yea, 02 and CH4

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UnkleRhaukus
  • UnkleRhaukus
that's right. do you know what products will be formed in a complete combustion?
anonymous
  • anonymous
mass of O2= 7.20x10^-3g Ch4( 1mol/16.042g) x( 2 mol O2/ 1molCh4) x(32.00g/1mol O2)=0.0287g
anonymous
  • anonymous
got this from an earlier problem, but the only diference is the 7.20 #
UnkleRhaukus
  • UnkleRhaukus
well in this case the mass is 4.6 milligrams instead of 7.2 milligrams
anonymous
  • anonymous
do you know how they arrived at 0.0287g?
UnkleRhaukus
  • UnkleRhaukus
Yeah you have the working above
UnkleRhaukus
  • UnkleRhaukus
The proper way to do this is finish the combustion equation so far we have \[\text O_2+\text{CH}_4\longrightarrow\]
UnkleRhaukus
  • UnkleRhaukus
can you tell me what products form in a complete combustion reaction
anonymous
  • anonymous
you mean from oxygen and methane?
UnkleRhaukus
  • UnkleRhaukus
what do you get when you burn all the methane in the oxygen , what is left?
anonymous
  • anonymous
we get just o2
UnkleRhaukus
  • UnkleRhaukus
all of the atoms in the products should be the same as the atom in the reactants, however, they molecules will have changed
anonymous
  • anonymous
yea, reactant should equal products after chemical reaction
UnkleRhaukus
  • UnkleRhaukus
What are the products ?
anonymous
  • anonymous
carbon dioxide and water
UnkleRhaukus
  • UnkleRhaukus
That's right!
UnkleRhaukus
  • UnkleRhaukus
so the (unballanced) reaction is\[\text O_2+\text{CH}_4\longrightarrow \text{CO}_2+\text H_2\text O\]
UnkleRhaukus
  • UnkleRhaukus
Can you ballance the equation so that the number of atoms of each element is the same on both sides of the equation ?
UnkleRhaukus
  • UnkleRhaukus
The C is already balanced, balance the H , then O

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