samigupta8
  • samigupta8
in the system shown,the initial acceleration of the wedge of mass 5M is
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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samigupta8
  • samigupta8
|dw:1378474791704:dw|
anonymous
  • anonymous
@uri , @Mashy , can you help her?
JT950
  • JT950
where is 5M?

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More answers

samigupta8
  • samigupta8
the biggest block is of 5M
JT950
  • JT950
u mean that 2M?
samigupta8
  • samigupta8
no no i want to say that wedge if in centre |dw:1378480222105:dw|
JT950
  • JT950
oh
JT950
  • JT950
consider all frictionless?
samigupta8
  • samigupta8
yaaa ryt
samigupta8
  • samigupta8
do u know how to solve it
JT950
  • JT950
do you mean angular acceleration or linear??
samigupta8
  • samigupta8
linear
JT950
  • JT950
What is the answer?
samigupta8
  • samigupta8
2g/23
anonymous
  • anonymous
it is 2g/3 is not it ?
anonymous
  • anonymous
2g/3 is the acceleration of the M..
anonymous
  • anonymous
well according to me it should be 2g/15.. since the mass is 5M.. the acceleration should be 5 times lesser!
samigupta8
  • samigupta8
bt it's given as 2g/23
anonymous
  • anonymous
yea.. i m trying to figure whats wrong in my method
samigupta8
  • samigupta8
okkk.
JT950
  • JT950
|dw:1378490613120:dw|
samigupta8
  • samigupta8
how do u get that the acceleration of M is 2g/3
JT950
  • JT950
When the 5M wedge is fixed,the 2M has 2Mg force downward , a=F/m=2Mg/3M=2g/3
samigupta8
  • samigupta8
u hve considered 2M and M as a single system
JT950
  • JT950
The question is initial acceleration?
samigupta8
  • samigupta8
yaaa
JT950
  • JT950
When fixed, the acceleration is to be that . When initially not fixed , the acceleration won't have too much different
experimentX
  • experimentX
looks like i got close to @Mashy add 2M to 5M, you will get 2g/21
samigupta8
  • samigupta8
then i mst say that u all r correct and that answer should be wrong bcuz so many of u r getting it and i cn't ignore the fact dat u all r agreeing 2 same ans
samigupta8
  • samigupta8
okkk..

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