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@uri , @Mashy , can you help her?
where is 5M?
the biggest block is of 5M
u mean that 2M?
no no i want to say that wedge if in centre |dw:1378480222105:dw|
consider all frictionless?
do u know how to solve it
do you mean angular acceleration or linear??
What is the answer?
it is 2g/3 is not it ?
2g/3 is the acceleration of the M..
well according to me it should be 2g/15.. since the mass is 5M.. the acceleration should be 5 times lesser!
bt it's given as 2g/23
yea.. i m trying to figure whats wrong in my method
how do u get that the acceleration of M is 2g/3
When the 5M wedge is fixed,the 2M has 2Mg force downward , a=F/m=2Mg/3M=2g/3
u hve considered 2M and M as a single system
The question is initial acceleration?
When fixed, the acceleration is to be that . When initially not fixed , the acceleration won't have too much different
looks like i got close to @Mashy add 2M to 5M, you will get 2g/21
then i mst say that u all r correct and that answer should be wrong bcuz so many of u r getting it and i cn't ignore the fact dat u all r agreeing 2 same ans