anonymous
  • anonymous
Determine solution set of the inequality \[|x-1|\geq 3|x+1|\]
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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terenzreignz
  • terenzreignz
Interesting :) We can always bring the 3 inside the absolute value... \[\Large |x-1 |\ge |3x + 3|\]
terenzreignz
  • terenzreignz
Or... wait... rethinking...
terenzreignz
  • terenzreignz
Might be better to divide both sides by |x+1| instead \[\Large \left|\frac{x-1}{x+1}\right|\ge 3\]

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anonymous
  • anonymous
hmm
terenzreignz
  • terenzreignz
So that this means either \[\Large \frac{x-1}{x+1}\ge 3\]or \[\Large \frac{x-1}{x+1}\le -3\]
anonymous
  • anonymous
the solution is -2
terenzreignz
  • terenzreignz
Patience. Solve this one: \[\Large \frac{x-1}{x+1}\ge 3\]
anonymous
  • anonymous
ok..

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