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anonymous

  • 2 years ago

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  1. anonymous
    • 2 years ago
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  2. ganeshie8
    • 2 years ago
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    average rate of change = change in y / change in x

  3. ganeshie8
    • 2 years ago
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    you're going from x=3 to x=5 so, chang ein x = 5-3 = 2

  4. ganeshie8
    • 2 years ago
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    do u knw how to find change in y, from the given table ?

  5. anonymous
    • 2 years ago
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    But what about the 1 ?

  6. anonymous
    • 2 years ago
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    And no , all of this is confusing to me :(

  7. ganeshie8
    • 2 years ago
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    its okay to get confuse when u start... did u get how we got the change in x ?

  8. anonymous
    • 2 years ago
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    Yes, we subtracted them? :o

  9. ganeshie8
    • 2 years ago
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    yes, now look at table. and tell me wats the y value, when x = 5 and when x = 3

  10. anonymous
    • 2 years ago
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    When x=5 , the y value is -2 . When x=3 , the y value is 4

  11. ganeshie8
    • 2 years ago
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    excellent ! so change in y = -2-4 = -6

  12. ganeshie8
    • 2 years ago
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    average rate of change = change in y / change in x = -6/2 = -3

  13. ganeshie8
    • 2 years ago
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    see if that makes sense

  14. anonymous
    • 2 years ago
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    That does makes sense ! :D

  15. ganeshie8
    • 2 years ago
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    cool :)

  16. anonymous
    • 2 years ago
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    Thank you so much, I have a few more questions? Would you be willing to help?

  17. ganeshie8
    • 2 years ago
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    sure ask :)

  18. anonymous
    • 2 years ago
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    I will attach it as a picture so it will be easier :)

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  19. ganeshie8
    • 2 years ago
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    find m, the rate of change of first

  20. ganeshie8
    • 2 years ago
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    (-1, 3) and (1 , 7)

  21. ganeshie8
    • 2 years ago
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    those are the given points

  22. ganeshie8
    • 2 years ago
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    (-1, 3) and (1 , 7) x1 y1 x2 y2

  23. ganeshie8
    • 2 years ago
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    rate of change , m = change in y / change in x = y2-y1 / x2-x1

  24. ganeshie8
    • 2 years ago
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    = 7-3 / 1--1 = 4/2 =2 so, m = 2

  25. anonymous
    • 2 years ago
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    Right :) I'm working it out on paper with you :P

  26. ganeshie8
    • 2 years ago
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    now, use this :- equation of line in slope, point form is, y - y1 = m(x-x1) plugin values :)

  27. anonymous
    • 2 years ago
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    That would be y - 3 = 2 (x - (-1)) ?

  28. ganeshie8
    • 2 years ago
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    Yes !

  29. anonymous
    • 2 years ago
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    Yay !!

  30. anonymous
    • 2 years ago
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    So is that it ? :o

  31. ganeshie8
    • 2 years ago
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    not yet, thats one equation. we could have used the second point aswell... let me do it for you :)

  32. anonymous
    • 2 years ago
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    Oh , okay :) Thank you !

  33. ganeshie8
    • 2 years ago
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    slope m = 2, second point (1 , 7) so m = 2, x1 = 1, y1=7 y-y1 = m(x-x1) plugin values now

  34. ganeshie8
    • 2 years ago
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    y-7 = 2(x-1)

  35. ganeshie8
    • 2 years ago
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    thats the second equation. now see which one exists in the given options , and tick that one...

  36. anonymous
    • 2 years ago
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    It's option 2 ! :)

  37. anonymous
    • 2 years ago
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    You helped me understand this ! Thank you :D

  38. ganeshie8
    • 2 years ago
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    Yes ! takes time to master these... i see you're already getting good at these :)

  39. anonymous
    • 2 years ago
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    I have 3 more questions left and 2 are easy , once I answer those may you help me with the very last question ?? Pleasee :p

  40. ganeshie8
    • 2 years ago
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    np, i hav time :)

  41. ganeshie8
    • 2 years ago
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    just holler when u r done wid the two prblms... ;)

  42. anonymous
    • 2 years ago
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    Haha okay !! :)

  43. anonymous
    • 2 years ago
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    Okay here's the last question :) Jack and Jill had 3 pails of water. Each trip up the hill, Jack and Jill obtained 1 more bucket of water. Which of the graphs below represents Jack and Jill's number of pails over time?

  44. ganeshie8
    • 2 years ago
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    check ur 3rd & 4th graphs. they are same !

  45. anonymous
    • 2 years ago
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    That's how it is on my quiz :( It's probably an error ... Is there anyway to do this and figure out the answer and see if it's on one of the graphs ? If not , I don't think my teacher will deduct points for the question being incorrect lol

  46. ganeshie8
    • 2 years ago
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    ohk, but wat wud u pick whe u have two exact same graphs ?

  47. anonymous
    • 2 years ago
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    Ugh I'm just going to chose an answer and tell my teacher there was an error with the questions . Thank you though :)

  48. ganeshie8
    • 2 years ago
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    good :) here is how we solve it :- since to start with, they have 3 pails of water, that means, the line must cit the y- axis at 3

  49. ganeshie8
    • 2 years ago
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    since the line is cutting y-axis at 3 only in 3rd & 4th graphs, one of them must be ur answer

  50. ganeshie8
    • 2 years ago
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    and since, both graphs are exact same, u toss a coin and pick one

  51. anonymous
    • 2 years ago
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    Haha okay :) Thank you so much for your help :)

  52. ganeshie8
    • 2 years ago
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    np :) goodluck wid ur assignment :)

  53. anonymous
    • 2 years ago
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    WAITTT ! This one ?? :o

  54. anonymous
    • 2 years ago
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    Can you help ? :o

  55. ganeshie8
    • 2 years ago
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    ha, take first equation, and solve x

  56. ganeshie8
    • 2 years ago
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    first equaiton :- 2x+4 = 3x-11

  57. ganeshie8
    • 2 years ago
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    can you solve x ?

  58. anonymous
    • 2 years ago
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    Yes, give me a minute :)

  59. ganeshie8
    • 2 years ago
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    take ur time =)

  60. anonymous
    • 2 years ago
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    The answer is 3 :)

  61. anonymous
    • 2 years ago
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    Second one is 16

  62. anonymous
    • 2 years ago
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    I need help solving the last one ...

  63. ganeshie8
    • 2 years ago
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    second one is 16 \(\checkmark \)

  64. ganeshie8
    • 2 years ago
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    but first one is not 3

  65. anonymous
    • 2 years ago
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    It's not ? :( What's the first one ?

  66. ganeshie8
    • 2 years ago
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    2x+4 = 3x-11 subtract 2x both sides 4 = x - 11 add 11 both sides 15 = x

  67. ganeshie8
    • 2 years ago
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    first one is 15

  68. anonymous
    • 2 years ago
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    Ohhhhh ! I know what I did wrong ! I added 3x and 2x by mistake ! haha

  69. ganeshie8
    • 2 years ago
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    :) i thought so... third equation :- \(\large \frac{2x+1}{3} = \frac{x+6}{2}\)

  70. ganeshie8
    • 2 years ago
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    cross multiply

  71. anonymous
    • 2 years ago
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    How would I start ? :( I'm no good in cross multiplying ..

  72. ganeshie8
    • 2 years ago
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    \(\large \frac{2x+1}{3} = \frac{x+6}{2}\) \(\large 2(2x+1) = 3(x+6)\)

  73. anonymous
    • 2 years ago
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    Omg that makes sense -.- ! Okay I understand now !

  74. ganeshie8
    • 2 years ago
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    cool :) solve x

  75. ganeshie8
    • 2 years ago
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    \(\large \frac{2x+1}{3} = \frac{x+6}{2}\) \(\large 2(2x+1) = 3(x+6)\) \(\large 4x+2 = 3x+18\) solve x

  76. anonymous
    • 2 years ago
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    4x + 2 = 3x + 18 ? Then solve ?

  77. ganeshie8
    • 2 years ago
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    yes !

  78. anonymous
    • 2 years ago
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    Okay one moment !

  79. ganeshie8
    • 2 years ago
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    oki

  80. anonymous
    • 2 years ago
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    Is x = -16 ?

  81. ganeshie8
    • 2 years ago
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    \(\large \frac{2x+1}{3} = \frac{x+6}{2}\) \(\large 2(2x+1) = 3(x+6)\) \(\large 4x+2 = 3x+18\) subtract 3x both sides \(\large x+2 = 18\)

  82. ganeshie8
    • 2 years ago
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    that gives, x = ?

  83. anonymous
    • 2 years ago
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    Oh sorry I subtracted 4x by mistake !

  84. ganeshie8
    • 2 years ago
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    ok.. x = ?

  85. anonymous
    • 2 years ago
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    One sec

  86. ganeshie8
    • 2 years ago
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    \(\large \frac{2x+1}{3} = \frac{x+6}{2}\) \(\large 2(2x+1) = 3(x+6)\) \(\large 4x+2 = 3x+18\) subtract 3x both sides \(\large x+2 = 18\) subtract 2 both sides \(\large x = 16\)

  87. anonymous
    • 2 years ago
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    Should be 16 !

  88. ganeshie8
    • 2 years ago
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    x = 16 ! :)

  89. anonymous
    • 2 years ago
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    Yay :D

  90. anonymous
    • 2 years ago
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    So equations 1 and 3 have the same solution !

  91. ganeshie8
    • 2 years ago
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    yes ! so we got, first one, x = 15 second one, x = 16 third one, x = 16

  92. ganeshie8
    • 2 years ago
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    careful madam, equations 2 and 3 have the same solution

  93. anonymous
    • 2 years ago
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    THANK YOU THANK YOU THANK YOU !! :) & yes I got confused haha but now i get it :)

  94. ganeshie8
    • 2 years ago
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    glad to hear that :) you're wlcme !!

  95. anonymous
    • 2 years ago
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    Are you willing to help me out with 4 more questions ? And that it for the day !! Haha

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